All categories

2 years ago

Which of the following situations could be represented by the expression −14+(−7)? Select two that apply.

Mathematics

1 answer:

aliya0001 [1]2 years ago

6 0

Answer:

Step-by-step explanation:

Owing someone meand you have to give them money and therefore is represented ad a negative number.

-14 + (-7) is the same as -14 - 7

You might be interested in

X⁴+x²+1+x⁴64445555555555555555<br><br>

bazaltina [42]

Answer:

2x⁴ + x² + 64445555555555555556

3 0

2 years ago

Find the two missing terms of the sequence and determine if the sequence is arithmetic, geometric, or neither.

wolverine [178]

-5, -7
The sequence is arithmetic.

6 0

2 years ago

Peggy is thinking of a number such that when twice the number is added to three times one more than the number she gets the same

mars1129 [50]

Answer:

-7

Step-by-step explanation:

Lets assume the number Peggy is thinking of be "x".

Now as given, when twice the number is added to three times one more than the number. We can write it as

∴ $2x+3(x+1)$ --- Equation 1

Again, it is given that Peggy gets the same result as when she multiplies four times one less than the number.

∴ $4(x-1)$ -- equation 2

Next, we can equate both the equation 1 and 2 as it is given that result is same.

$2x+3(x+1)= 4(x-1)$

Let´s distribute 3 into $(x+1)$ and 4 into $(x-1)$

⇒ $2x+3x+3=4x-4$

⇒ $5x+3=4x-4$

Subtract both side by 4x and 3

∴ $x=-7$

∴ Peggy was thinking of -7

4 0

2 years ago

Help please i don’t know how to do it

Norma-Jean [14]

Answer:

Step-by-step explanation:

$\frac{dy}{dx}=x^{2}(y-1)\\\frac{1}{y-1} \text{ } dy=x^{2} \text{ } dx\\\int \frac{1}{y-1} \text{ } dy=\int x^{2} \text{ } dx\\\ln|y-1|=\frac{x^{3}}{3}+C\\$

From the initial condition,

$\ln|3-1|=\frac{0^{3}}{3}+C\\\ln 2=C$

So we have that $\ln |y-1|=\frac{x^{3}}{3}+\ln 2\\e^{\frac{x^{3}}{3}+\ln 2}=y-1\\2e^{\frac{x^{3}}{3}}=y-1\\y=2e^{\frac{x^{3}}{3}}+1$

4 0

2 years ago

PLEASE HELP!! i dont understand it

andreev551 [17]

Answer:

a. y^ -1 = e^x +2

Step-by-step explanation:

y = ln (x-2)

Exchange x and y

x = ln (y-2)

Solve for y

Raise each side with a base of e

e^ x = e^(ln(y-2)

e^x = y-2

Add 2 to each side

e^x +2 =y

6 0

2 years ago