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2 years ago

Describe the work performed by a ski lift in terms of kinetic and gravitational potential energy

2 answers:

7 0

Explanation : When the lift falls, then the gravitational energy changed into the kinetic energy. Gravitational potential is associated with the mass of the lift and its position. When lift starts from rest , the mechanical energy of the lift change in the form of potential energy.

When the lift down than the potential energy lost and kinetic energy is gained. Lift loses height and gains speed.

The work is performed by the lift, when lift covers the distance against the gravitational force.

Whitepunk [10]2 years ago

7 0

In order to understand how kinetic and potential energy works in an ski lift it is necessary to know its terms

Potential energy is the energy that a body located from its height above the ground has

Kinetic energy is the energy of a body that is in motion

for the ski lift:

Kinetic Energy: When the ski lift moves from floor to floor

Potential Energy: When the ski lift is standing on the floor and people enter.

Gravitational energy: the chairlift uses the force of gravity to lower and change from potential energy to kinetic energy, with its own weight

I hope its help you

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The first and second coils have the same length, and the third and fourth coils have the same length. They differ only in the cr

tatyana61 [14]

Answer:

The ratio of the resistances of second coil to the first coil is the ratio of square of radius of the first coil to the square of radius of second coil.

And

The ratio of the resistances of fourth coil to the third coil is the ratio of square of radius of the third coil to the square of radius of fourth coil.

Explanation:

The resistance of the coil is directly proportional to the length of the coil and inversely proportional to the area of coil and hence inversely proportional to the square of radius of the coil.

So, the ratio of the resistances of second coil to the first coil is the ratio of square of radius of the first coil to the square of radius of second coil.

And

The ratio of the resistances of fourth coil to the third coil is the ratio of square of radius of the third coil to the square of radius of fourth coil.

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2 years ago

Plz help me ASAP How does sound travel from its source to your ear??? 1. By changes in air pressure 2. By vibrations in wires or

Sholpan [36]

Answer:

2. By vibrations in wires or strings.

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3 years ago

Two small nonconducting spheres have a total charge of 90.0 C.

valentina_108 [34]

Answer: (a) Smaller charge is $2.7 \times 10^{-5} C$ and larger charge is $11.7 \times 10^{-5} C$ .

(b) Smaller charge is $-11.4 \times 10^{-5}$ and larger charge is $9.1 \times 10^{-5}$ .

Explanation:

(a) When both the spheres have same charge then force is repulsive in nature as like charges tend to repel each other.

Therefore, total charge on the two non-conducting spheres will be calculated as follows.

$Q_{1} + Q_{2} = 90 \mu \times \frac{10^{-6}C}{1 \muC}$

= $9 \times 10^{-5} C$

Therefore, force between the two spheres will be calculated as follows.

F = $k\frac{Q_{1}Q_{2}}{r^{2}}$

12 N = $\frac{(9 \times 10^{9} Nm^{2}/C^{2})Q_{1}Q_{2}}{(0.28 m^{2})}$

$Q_{1}Q_{2} = 0.104 \times 10^{-9} C^{2}$

or, $Q_{1}(9 \times 10^{-5} - Q_{1}) = 0.104 \times 10^{-9} C^{2}$

$9 \times 10^{-5}Q_{1} - Q^{2}_{1} = 0.104 \times 10^{-9} C^{2}$

$Q^{2}_{1} - 9 \times 10^{-5}Q_{1} + 0.104 \times 10^{-9} = 0$

$Q_{1} = 11.7 \times 10^{-5} C, 2.7 \times 10^{-5} C$

This means that smaller charge is $2.7 \times 10^{-5} C$ and larger charge is $11.7 \times 10^{-5} C$ .

(b) When force is attractive in nature then it means both the charges are of opposite sign.

Hence, total charge on the non-conducting sphere is as follows.

$Q_{1} + (-Q_{2}) = 90 \mu \times \frac{10^{-6}C}{1 \muC}$

$Q_{1} - Q_{2} = 9 \times 10^{-5} C$

Now, force between the two spheres is calculated as follows.

F = $k\frac{Q_{1}Q_{2}}{r^{2}}$

12 N = $\frac{(9 \times 10^{9} Nm^{2}/C^{2})Q_{1}Q_{2}}{(0.28 m^{2})}$

$Q_{1}Q_{2} = 0.104 \times 10^{-9} C^{2}$

$Q_{1}(Q_{1} - 9 \times 10^{-5}) = 0.104 \times 10^{-9} C^{2}$

$Q^{2}_{1} - 9 \times 10^{-5}Q_{1} = 0.104 \times 10^{-9} C^{2}$

$Q_{1} = -11.4 \times 10^{-5}, 9.1 \times 10^{-5}$

Hence, smaller charge is $-11.4 \times 10^{-5}$ and larger charge is $9.1 \times 10^{-5}$ .

8 0

2 years ago

The diagram does not represent a real electric field because the field lines__<br> NEED ANSWERS NOW

prohojiy [21]

Answer:

cross at many points

Explanation:

According to the diagram it does not shows the real electric field as the electric field does not intersect with each other but according to the given diagram many lines are intersected with each other

So the correct option is C as it would be crossed at many points

Hence, the same would be relevant

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2 years ago

Homework

yarga [219]

Answer:

Please reframe your questions

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2 years ago