Answer
given,
L(t) = 10 - 3.5 t
mass of particle = 2 Kg
radius of the circle = 3.1 m
a) torque
τ =
τ =
τ = -3.5 N.m
Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.
L decreases the angular acceleration upward. so, net torque is upward.
b) Moment of inertia of the particle
I = m R^2
I = 2 x 3.1²
I = 19.22 kg.m²
L = I ω
ω =
ω =
ω =
A = 0.52 rad/s B = -0.182 rad/s²
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Answer:0.502kg
Explanation:
F4om the relation
Power x time = mass x latent heat of vapourization
P.t=ML
1260 * 15 *60 = M * 22.6 * 10^5
M= 1134000/(22.6 *10^5)
M=0.502kg=502g