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2 years ago

I need help please?!!!

Mathematics

2 answers:

mash [69]2 years ago

5 0

Answer:

y-axis

because you plot 0 on the x-axis which is horizontal line then you go up 4 on the y-axis which is the vertical line so it's located on the y-axis.

Lubov Fominskaja [6]2 years ago

3 0

Y-axis, because what i’ve been taught with coordinates, is you crawl before you walk which means is first it’s x-axis then y-axis. so (0,4) would be on the y-axis. :)

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Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation

lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=73$

Step-by-step explanation:

$First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}$

$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$

$S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\$

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73$

5 0

2 years ago

Please Help! Which of the following equations, when graphed, results in the parabola depicted above? (I'll put a screenshot of t

kykrilka [37]

Answer:

Step-by-step explanation:

The zeroes are 0 and 4 and the vertex is at (2, -4).

f(x) = (x - 2)^2 - 4

5 0

2 years ago

Read 2 more answers

What is the value of the x-coordinate of 2x+3y=144;y-x=24

erica [24]

The value of x - coordinate is 14.4

Solution:

Given that we have to find the x -coordinate of the system

Given system of equations are:

2x + 3y = 144 -------- eqn 1

y - x = 24 --------- eqn 2

Solve the above system of equations to find the x - coordinate

From eqn 2,

y = 24 + x ------- eqn 3

Substitute eqn 3 in eqn 1

2x + 3(24 + x) = 144

2x + 72 + 3x = 144

Add the like terms

5x + 72 = 144

5x = 144 - 72

5x = 72

Divide 72 by 5

x = 14.4

Thus the x - coordinate of the system is 14.4

3 0

3 years ago

Part A: Solve -vp + 30 < 45 for v .. show your work.

lorasvet [3.4K]

-vp + 30 < 45....for v
-vp < 45 - 30
-vp < 15
-v < 15/p
v > -15/p <==
============
3w - 6r = 30 ...for r
-6r = 30 - 3w
r = (30 - 3w) / -6
r = -5 + 1/2w...or r = 1/2w - 5 <==

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2 years ago

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Make x the subject of W= y+x/y

shutvik [7]

What it for like what subject

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