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2 years ago

11

What does the word resolution mean in the sentence "By 1915, the British Roentgen Society had adopted a resolution to protect pe

ople from overexposure to X-rays"?

1 answer:

iris [78.8K]2 years ago

5 0

Resolution in this sentence refers to a solution to the problem

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Suppose you take

kati45 [8]

Answer:

a current will be induced.

Explanation:

4 0

2 years ago

Read 2 more answers

The magnitude of the electric field between two parallel charged plates is 200. An electron moves to the negative plate 5. 0 cm

Mama L [17]

The potential difference between the two ends of the circuit is the electric potential difference. The electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

<h3>What is an electric field?</h3>

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

The given data in the problem is given by;

E is the electric field = (200 N/C)

d is the distance = 5.0 cm.=0.05 m

Q is the charge of electrons= 1.602 x 10^-19 C

The formula for electric potential is given by;

$\rm V=Ed$

$\rm V=Ed \\\\ \rm V=200 \times 0.05 \\\\ \rm V= 10 \frac{Nm}{C} = 10 \frac{J}{C} = 10 V.$

The work is defined as the product of the potential difference and charge of an electron.

$\rm W= 10 \times 1.602 x 10^{-19} \\\\\ \rm W= 1.6 x 10^{-18 }J$

Hence the electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

To learn more about the electric field refer to the link;

brainly.com/question/15071884

8 0

2 years ago

The mass of the block in the drawing is 10 kg. The coefficient of static friction between the block and the vertical wall is 0.5

antiseptic1488 [7]

Answer:

The minimum force to start the block moving up the wall = 49 N

Explanation:

Friction: This is the force that tend to oppose the motion of two bodies in contact. The S.I unit of frictional force is Newton (N)

The minimum force required to start the block moving up the wall = Frictional Force.

I.e F = Frictional force.

And, F = μR..........................Equation 1

Where μ = coefficient of static friction, R = Normal reaction.

But R = mg ( on a level surface).................. Equation 2

Where m = mass, g = acceleration due to gravity.

Given: m = 10 kg,

Constant: g = 9.8 m/s²

substituting these values into Equation 2

R = 10 × 9.8

R = 98 N.

Also given: μ = 0.50

Substituting these values into equation 1

F = 98 × 0.5

F = 49 N.

Therefore The minimum force to start the block moving up the wall = 49 N

3 0

2 years ago

Two steel guitar strings have the same length. String A has a diameter of 0.513 mm and is under 403 N of tension. String B has a

Mnenie [13.5K]

Answer:

$\frac{v_{A}}{v_{B}} = 1.785$

Explanation:

$T_{A}$ = Tension force in string A = 403 N

$T_{B}$ = Tension force in string B = 800 N

$d_{A}$ = diameter of string A = 0.513 mm

$d_{B}$ = diameter of string B = 1.29 mm

$v_{A}$ = wave speed of string A

$v_{B}$ = wave speed of string B

Ratio of the wave speeds is given as

$\frac{v_{A}}{v_{B}} = \sqrt{\frac{T_{A}}{T_{B}}} \left ( \frac{d_{B}}{d_{A}} \right )$

$\frac{v_{A}}{v_{B}} = \sqrt{\frac{403}{800}} \left ( \frac{1.29}{0.513} \right )$

$\frac{v_{A}}{v_{B}} = 1.785$

5 0

2 years ago

A boy on a bicycle approaches a brick wall as he sounds his horn at a frequency 400 hz. the sound he hears reflected back from t

Mashutka [201]

As the question is about changing in frequency of a wave for an observer who is moving relative to the wave source, the concept that should come to our minds is "Doppler's effect."

Now the general formula of the Doppler's effect is:
$f = (\frac{g + v_{r}}{g + v_{s}})f_{o}$ -- (A)

Note: We do not need to worry about the signs, as everything is moving towards each other. If something/somebody were moving away, we would have the negative sign. However, in this problem it is not the issue.

Where,
g = Speed of sound = 340m/s.
$v_{r}$ = Velocity of the receiver/observer relative to the medium = ?.
$v_{s}$ = Velocity of the source with respect to medium = 0 m/s.
$f_{o}$ = Frequency emitted from source = 400 Hz.
$f$ = Observed frequency = 408Hz.

Plug-in the above values in the equation (A), you would get:

$408 = ( \frac{340 + v_{r}}{340 + 0})*400$

$\frac{408}{400} = \frac{340 + v_{r}}{340}$

Solving above would give you,
$v_{r}$ = 6.8 m/s

The correct answer = 6.8m/s

7 0

2 years ago