Answer:
A.Glycogenesis: Glycogen synthase
B. Glucogenesis: Fructose 1,6 biphosphate phosphatase
C. Urea cycle : Carbamoyl phosphate synthetase
D.Fatty acid synthesis: Acetyl CoA carboxylase
E.Glycolysis : Phosphofructokinase 1
F. Pentose phosphate pathway: Glucose-6-phosphate dehydrogenase
Explanation:
A. Glycogen synthase converts glucose into glycogen during glycogenesis.
B. Fructose 1,6 biphosphate phosphatase catalyzes condensation of dihydroxyacetone phosphate (DHAP) and glyceraldehyde-3-phosphate during glucogenesis.
C. Carbamoyl phosphate synthetase I catalyses production of arbamoyl phosphate during urea cycle.
D. Carboxylase controls fatty acid metabolism.
E. The phosphofructokinase 1 is an important enzyme that regulate formation of two-phosphate sugar molecules during glycolysis.
F. Glucose-6-phosphate dehydrogenase participates in the pentose phosphate pathway. This pathway gives reducing energy to cells.
The term "IMViC" is an acronym for each of these tests. "I" is for indole test; "M" is for methyl red test; "V" is for Voges-Proskauer test, and "C" is for citrate test. The lower case "i" is merely for "in" as the Citrate test requires coliform samples to be placed "in Citrate". Triple sugar iron test (TSI), Urease Test and Malonate Test are also included in this test.
For each of the tests, different reagents are added to the species are inoculated and tested.
For Salmonella sp. the IMViC Test result is:
Indole - negative
Methyl red - Positive
Voges-Proskauer - negative
Citrate - positive
Answer:
LLgg, Llgg , two out of 16
Explanation:
Given,
Dominant - Long wings and Gray color
Recessive - Short wings and Brown color
Let the allele for long wings be "L" and the allele for short wings be "l".
Let the allele for brown color be "g" and allele for gray color be "G"
Genotype of parents
LlGg
Gametes of the parent
LG, Lg, lG, lg
Dihybrid cross is between LlGg and LlGg
The offspring produces will be as follows -
LG Lg lG lg
LG LLGG LLGg LlGG LlGg
Lg LLGg LLgg LlGg Llgg
lG LlGG LlGg llGG llGg
lg LlGg Llgg llGg llgg
Offspring with long wings and brown color – LLgg, Llgg , two out of 16
The question is incomplete, however, the statements associated with this question is given in the comments and here as well:
Neither facilitated diffusion nor osmosis requires cell energy.
Diffusion of gases and other small molecules requires no energy on the part of the cell.
Active transport requires cell energy and osmosis doesn't.
Both endocytosis and active transport require cell energy.
Answer:
The correct answer is - Active transport requires cell energy and osmosis doesn't.
Explanation:
Osmosis is an example of passive transport as it does not require energy to facilitate the movement of solvent In the process of osmosis,. It moves from high concentration to low concentration through the semipermeable membrane which is along the gradient so no requirement of energy.
In the case of Active transport, it requires energy to facilitate the movement of transport as it is the movement of a substance from low concentration to a high concentration area that is against the concentration gradient.
Answer:
Geosphere
Explanation:
the geosphere contains the rocks that make up the earth, and the lithosphere contains rocks :)
