Why not draw the graph of y=|x|? It has a v-shape, and the vertex is at (0,0).
The graph of f(x) = |x| - 3 looks exactly the same, EXCEPT that the whole graph of |x| is shifted 3 units downward. The smallest value that y can have is therefore -3.
Can you now figure out the range of f(x)?
Answer:
polkadot's strips
plain stripes
polkadot's plain
Step-by-step explanation:
3
Answer:
as a fraction 1/4 as a decimal .25
Step-by-step explanation:
The function
... f(x) = (x+2)/(x-1) = 1 + 3/(x-1)
is symmetrical about the line y=x, hence is its own inverse.
We can evaluate the desired derivative directly.
... f'(x) -3/(x-1)²
so f'(2) is
... f'(2) = -3/(2-1)²