Ways to increase friction
<span>- increase the roughness of the contact materials </span>
<span>- increase the pressure on the contact </span>
<span>Ways to decrease friction </span>
<span>- float the moving body on air </span>
<span>- suck out any air </span>
Answer:
Your question was incomplete so here is the complete question and answer.
Q. When exercising in the heat, which of the following hydration strategies is best for temperature regulation during an event (e.g., 10K race)
a) plain water
b) 5-7 percent glucose solution
c) Glucose polymer solution of 6-8 percent
d) There appears to be no difference among these different forms of hydration techniques relative to temperature regulation.
Ans. d) There appears to be no difference among these different forms of hydration techniques relative to temperature regulation.
Explanation:
Temperature Regulation is an important phenomenon for the person exposed to extreme hot conditions or weather. Exercising in hot conditions increase the body temperature. Greater and intense exercise, greater the production of heat. Then the heat dissipation takes place in the form of excessive sweating which results in dehydration. That was just the brief overview of temperature regulation. Above mentioned techniques are equally good hydration techniques so there is no difference at all. You can have a plain water or glucose solutions of above mentioned percentages.
Answer:
Frictional force, F = 45.9 N
Explanation:
It is given that,
Weight of the box, W = 150 N
Acceleration,
The coefficient of static friction between the box and the wagon's surface is 0.6 and the coefficient of kinetic friction is 0.4.
It is mentioned that the box does not move relative to the wagon. The force of friction is equal to the applied force. Let a is the acceleration. So,
Frictional force is given by :
F = 45.9 N
So, the friction force on this box is closest to 45.9 N. Hence, this is the required solution.
Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.
P=F/A