$a_n=a_{n-1}+5(-1)^n\\\\if\ n\ is\ even\ then:a_n=a_{n-1}+5(-1)^n=a_{n-1}+5\\\\if\ n\ is\ odd\ then:a_n=a_{n-1}+5(-1)^n=a_{n-1}-5\\\\a_1=5\\a_2=5+5=10\\a_3=10-5=5\\a_4=5+5=10\\a_5=10-5=5\\\vdots\\a_{343}=5\ \ \ \ (343\ is\ odd\ number)$

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2 years ago

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Given: angle 1 and angle 2 form a linear pair,

iris [78.8K]

Answer:

Look at the proof down

Step-by-step explanation:

The given is;

→ ∠1 and ∠2 form a linear pair

→ ∠1 ≅ ∠3

We want to prove;

→ ∠2 and ∠3 are supplementary

<em>We will write the proof in like a table</em>

1. ∠1 and ∠2 formed a linear pair ⇒ 1. Given

2. m∠1 + m∠2 = 180° ⇒ 2. Sum of angles on a straight line

3. ∠1 and ∠2 are supplementary angles ⇒ 3. Supplementary angles add up to 180°

4. ∠1 ≅ ∠3 ⇒ 4. Given

5. m∠2 + m∠3 = 180° ⇒ 5. Substitution method

6. ∠3 is a supplement of ∠2 ⇒ 6. Supplement of equal angles

7. ∠2 and ∠3 are supplementary ⇒ 7. Proved

8 0

2 years ago