Cost =16000
rate of depreciation = 35%
written down value = 2000
depreciation for one year =16000*35% = 5600
5600*2 = 11200+5600*6\12 = 2000
the car is 2.5 years old. It has been depreciated for 2 whole years and half
years.
Answer:
Solution given:
The area of a circle =80.86cm²
we have:
The area of a circle =πr²
substituting value of area of circle we get
80.86cm=3.14*r²
dividing both side by 3.14
80.86/3.14=3.14*r²/3.14
25.75=r²
doing square root on both side
r=5.07cm
<u>The</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>radius</u><u> </u><u>is</u><u> </u><u>5</u><u>.</u><u>0</u><u>7</u><u>cm</u>
SA = 1,226 in.² (Hope this helps!)
Step-by-step explanation:
the average change rate of a function f(x) in an interval [x1 .. x2] is
(f(x2) - f(x1)) / (x2 - x1)
in our case that is
(7000 - 2500) / (20 - 0) = 4500 / 20 = 225
the population changed in average by 225 people per year from 1900 to 1920.