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notsponge [240]

2 years ago

13

Help anyone pleaseLol

1 answer:

WITCHER [35]2 years ago

7 0

Answer:

its the sceond one

Step-by-step explanation:

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Let f(x)=x+8and g(x)=x^2-6x-7. Find f(g(2))

posledela

The answer is a. -7

1. Find g(2).

2. Find f(g(2)).

g(x) = x² - 6x - 7

x = 2 ⇒ g(2) = ?

g(2) = 2² - 6·2 - 7 = 4 - 12 - 7 = -15

2. f(x) = x + 8

g(2) = -15

f(g(2)) = f(-15) = -15 + 8 = -7

3 0

2 years ago

Find the unknown angle measure by solving for the given variable.

pochemuha

Answer:

10 1/2

Step-by-step explanation:

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ElenaW [278]

Its positive for the supermarkets oweners

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2 years ago

the distance around a track is 400m. if you take 14 laps around the track what is the total distance you walk? use mental math

Olegator [25]

to do it in mental math: you can ignore the zeroes in 400 for now.

4*14 = 4*10 + 4*4 = 40 + 16 = 56

now add the zeroes back on: 5600m

6 0

2 years ago

Read 2 more answers

In 1967, New Zealander Burt Munro set the world record for an Indian motorcycle, on the Bonneville Salt Flats in Utah, with a ma

bagirrra123 [75]

Answer:49 sec

Step-by-step explanation:

Given

Maximum speed to reach is 183.58 mi/h

Length of course is 5 mi

acceleration rate is defined by 60mi/h in 4 sec

therefore acceleration(a) $=\frac{v-u}{t}$

$a=\frac{60\times 60\times 60}{4}$

$a=54\times 10^3 mi/h^2$

To reach a speed of 183.58mi/h with an acceleration of $54\times 10^3 mi/h^2$

Using equation of motion

v=u+at

$183.58=0+(54\times 10^3)t$

$t=\frac{183.58}{54\times 10^3}$

t=0.00339 hours

t=12.23 s reach maximum speed

To complete course it takes

$s=ut+\frac{1}{2}at^2$

$5=0+\frac{1}{2}\times 54\times 10^3 \times t^2$

t=0.01360 hour

or $t=48.98\approx 49 s$

7 0

2 years ago