Ask question

Ask question

All categories

2 years ago

15

Help please its URGENT!!!!!!!!

2 answers:

Aneli [31]2 years ago

4 0

This is a relation but not a function.

Functions must have that there is a unique y for a given x, which clearly doesn't work here because all lines of a given x have 2 y-values. However, it is a relation because there is a given set of points which are defined to be within the set of the ellipse (if it's defined which members of two sets, the range and domain, go together, then you have a relation)

Alinara [238K]2 years ago

4 0

iam thinking its D but iam not 100% sure.

You might be interested in

Help plz and thanks

rodikova [14]

Answer:

6b

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

I need help. once again. bahahaha

katrin [286]

Answer:

letters d. and e.

5 0

2 years ago

What are the factors PLEASE HELP!!!

elena55 [62]

Answer:

The answer is (x-6) squared

4 0

2 years ago

Look at rectangle f, g, h, and j on the grid below. which rectangle has an area of 64 sqare units?

hichkok12 [17]

F= 9 x 7 = 63
G= 19 x 4 = 76
H= 12 x 4 = 48
J = 32 x 2 = 64
J is the answer

8 0

2 years ago

Given: Q=7m+3n,R=11-2m,s=n+5,and T =-m-3n+8 simplify Q-[R+S]-T

Gnesinka [82]

Answer:

Simplify

$Q-[R+S]-T$

The answer is:

$10m+5n-24$

Step-by-step explanation:

We have the expressions:

$Q=7m+3n\\R=11-2m\\S=n+5\\T=-m-3n+8$

Now, we need simplify:

$Q-[R+S]-T$

We need to replace each term by the expressions:

$7m+3n-[(11-2m)+(n+5)]-(-m-3n+8)$

We need to remember the rule of signs:

$-/-=+$

$-/+=-$

$+/+=+$

With this in mind we solve the parentheses:

$7m+3n-[(11-2m)+(n+5)]-(-m-3n+8)$

$7m+3n-[11-2m+n+5]+m+3n-8$

$7m+3n-11+2m-n-5+m+3n-8$

let's group common terms

$7m+3n-11+2m-n-5+m+3n-8\\7m+2m+m+3n-n+3n-11-5-8$

We must add and subtract common terms:

$7m+2m+m+3n-n+3n-11-5-8\\10m+5n-24$

The answer is:

$10m+5n-24$

7 0

3 years ago