The technique of matrix isolation involves condensing the substance to be studied with a large excess of inert gas (usually argon or nitrogen) at low temperature to form a rigid solid (the matrix). The early development of matrix isolation spectroscopy was directed primarily to the study of unstable molecules and free radicals. The ability to stabilise reactive species by trapping them in a rigid cage, thus inhibiting intermolecular interaction, is an important feature of matrix isolation. The low temperatures (typically 4-20K) also prevent the occurrence of any process with an activation energy of more than a few kJ mol-1. Apart from the stabilisation of reactive species, matrix isolation affords a number of advantages over more conventional spectroscopic techniques. The isolation of monomelic solute molecules in an inert environment reduces intermolecular interactions, resulting in a sharpening of the solute absorption compared with other condensed phases. The effect is, of course, particularly dramatic for substances that engage in hydrogen bonding. Although the technique was developed to inhibit intermolecular interactions, it has also proved of great value in studying these interactions in molecular complexes formed in matrices at higher concentrations than those required for true isolation.
80% like crisps
75% of the 80% like chocolate.
What percent of the total are the children who like chocolate and crisps?
75% of 80% = 60%
This 60% of children like chocolate and crisps
Answer:
With a 5-digit number, you have 5 choices for the first digit. There will be 4 digits left so you have 4 choices for the second digit. After you have chosen the first 2 digits there will be 3 remaining so you will have 3 choices for the third digit. Hence there are 2 choices for the fourth digit and only 1 choice for the fifth digit. Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 2 and 1
Answer:
the amount he paid is 36.06
Step-by-step explanation:
hope this helps
Answer:
B. Median is greater than the mean and the majority of data points are to the right of the mean.
Step-by-step explanation:
Mean = sum(x × p(x))
= (1×0.1)+(2×0.15)+(3×0.2)+(4×0.45)+(5×0.1)
= 3.3
Probability of more than 3.3 is:
0.45 + 0.1 = 0.55 > 0.5