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2 years ago

Please Help

Mathematics

1 answer:

kykrilka [37]2 years ago

5 0

Im pretty sure it would be 6x

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Staci is attending a music festival. The ticket to the festival costs $87.96 . Staci plans to purchase $30.00 t-shirts from the

mafiozo [28]

Step one: 200-87.96=112.04

Step two: 112.04÷30≈3.7

Step three: 3.7↔3

Answer: Staci can buy 3 shirts

5 0

2 years ago

Maria's family drove 140 mi to her grandparents' house and averaged 56 mi/h on the way there. On the return trip, they avera

GaryK [48]

Answer: 5.3 Hours

Step-by-step explanation: 140 mi there at 56 mi per hour would be 2.5 hours. Then back 140 mi at 50 mi/h would be 2.8. 2.5 plus a 2.8 is 5.3 hours

4 0

2 years ago

Can help me with this problem

Vinvika [58]

X • (2x+3)
may be answer

4 0

2 years ago

Read 2 more answers

Please answer correctly !!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!

Ugo [173]

Answer:

Step 3 they took the square root incorrectly

Step-by-step explanation:

5 ( x-2)^2 +6 = 86

Subtract 6 from each side

5 ( x-2)^2 +6 -6= 86-6

5 ( x-2)^2 = 80

Divide each side by 5

5 ( x-2)^2 /5 = 80/5

(x-2)^2 = 16

Take the square root of each side

sqrt((x-2)^2) = ±sqrt(16)

x-2 = ±4

4 0

2 years ago

The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre

Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : $a=-2$

Common difference : $d = 5 - (-2)$

$= 5 + 2$

$= 7$

nth term of an A.P. is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

$a_n=-2+(n-1)(7)$

According to the equation, $a_n>200$ .

$-2+(n-1)(7)>200$

$(n-1)(7)>200+2$

$(n-1)(7)>202$

Divide both sides by 7.

$(n-1)>28.857$

Add 1 on both sides.

$n>29.857$

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

$S_n=\dfrac{n}{2}[2a+(n-1)d]$

Substituting n=30, a=-2 and d=7, we get

$S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]$

$S_{30}=15[-4+(29)7]$

$S_{30}=15[-4+203]$

$S_{30}=15(199)$

$S_{30}=2985$

Therefore, the sum of all the terms in the progression is 2985.

6 0

2 years ago