Answer:
Step-by-step explanation:
a) x>0 → items can not be negative
b) c(2,000) = 5,000+1.3(2,000) = $7,600
c)5,000+1.3x<10,000
5,000-5,000+1.3x<10,000-5,000
1.3x<5,000
x<3846 items
Given Information:
Population mean = p = 60% = 0.60
Population size = N = 7400
Sample size = n = 50
Required Information:
Sample mean = μ = ?
standard deviation = σ = ?
Answer:
Sample mean = μ = 0.60
standard deviation = σ = 0.069
Step-by-step explanation:
We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10
np ≥ 10
50*0.60 ≥ 10
30 ≥ 10 (satisfied)
n(1 - p) ≥ 10
50(1 - 0.60) ≥ 10
50(0.40) ≥ 10
20 ≥ 10 (satisfied)
The mean of the sampling distribution will be same as population mean that is
Sample mean = p = μ = 0.60
The standard deviation for this sampling distribution is given by
Where p is the population mean that is proportion of female students and n is the sample size.
Therefore, the standard deviation of the sampling distribution is 0.069.
Answer:
<h3>The answer is option D.</h3>
Step-by-step explanation:
First we must first find the LCM
The LCM of x² + 3x + 2 and (x + 2)(x + 1 ) is
x² + 3x + 2
So we have
Hope this helps you
Answer:
its actually the one on the top right
Step-by-step explanation:
Hope it helps ;)
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