So let n be the smallest number. To have consecutive even integers each number goes up by 2 so n, n+2, n+4, n+6, n+8.
Therefore, n+n+2+n+4+n+6+n+8=290
5n+20=290
5n=270
n=54
Answer:
In this equation n = 15
Step-by-step explanation:
In order to find this, we first must make each term a base 3. Since 9 is 3 squared, we can change it easily to base 3.
3^5 * 9^5 = 3^n
3^5 * (3^2)^5 = 3^n
3^5 * 3^10 = 3^n
3^15 = 3^n
Now that we have both in simple term of 3 raised to a power, we can eliminate the 3's and see that 15 = n
Answer:
b -1
Step-by-step explanation:
it's the line that the curve ends on and is linear on
Answer: 3H+4C<_ 30
The coefficients of the variables H and C represent the number of batteries each toy helicopter and each toy car uses.
Step-by-step explanation:
Each toy helicopter uses 3 batteries, and each toy car uses 4 batteries.
Now let's check whether Vugar has enough batteries for 5 toy helicopters and 4 toy cars. To do this, we substitute H=5 and C= 4 in the given inequality:
Does Vugar have enough batteries to play with 5 toy helicopters and 4 toy cars?
No, because if you plug in the value for H and C:
3H + 4C<_ 30
3(5) + 4(4) <_30
15 + 16 <_ 30
31 <_ 30; false
Since the inequality is false, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.
Each toy helicopter uses 333 batteries, and each toy car uses 444 batteries.
No, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.
