Answer:
A. Total mass of each team
Explanation:
The side with the larger mass will end up pulling the side with the smaller mass
The question is incomplete. Here is the complete question.
The image below was taken with a camera that can shoot anywhere between one and two frames per second. A continuous series of photos was combined for this image, so the cars you see are in fact the same car, but photographed at differene times.
Let's assume that the camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately 5.3 meters. Using this information and the photo itself, approximately how fast did the car drive?
Answer: v = 6.5 m/s
Explanation: The question asks for velocity of the car. Velocity is given by:
The camera took 7 pictures of the car and knowing its length is 5.3, the car's displacement was:
Δx = 7(5.3)
Δx = 37.1 m
The camera delivers 1.3 frames per second and it was taken 7 photos, so time the car drove was:
1.3 frames = 1 s
7 frames = Δt
Δt = 5.4 s
Then, the car was driving:
v = 6.87 m/s
The car drove at, approximately, a velocity of 6.87 m/s
Answer:
Explanation:
Given
Ship A velocity is 40 mph and is traveling 35 west of north
Therefore in 2 hours it will travel
thus its position vector after two hours is
similarly B travels with 20 mph and in 2 hours
Thus distance between A and B is
Velocity of A
Velocity of B
Velocity of A w.r.t B
1 ft =12 in
4 in = 0.333 ft
volume = (п/4)*(0.333)² = 0.087 ft²
vol. flow = spead *volume
=3 ft/s * 0.087 ft²
vol flow = 0.261 ft³/s