If these coordinates are rotated 270° counterclockwise, the resulting coordinates will be;
<em>X' = (3, -1)</em>
<em>Y' = (2, -2)</em>
<em>Z' = (-1, -3)</em>
<h3>Rotation of coordinates</h3>
If the coordinates (x, y) is rotated 270° counterclockwise, the resulting coordinate point will be;
(x, y) - > (y, -x)
From the given triangles, the coordinate points are expressed as
<em>X = (1, 3)</em>
<em>Y = (2, 2)</em>
<em>Z = (3, -1)</em>
If these coordinates are rotated 270° counterclockwise, the resulting coordinates will be;
<em>X' = (3, -1)</em>
<em>Y' = (2, -2)</em>
<em>Z' = (-1, -3)</em>
Learn more on rotation here: brainly.com/question/26249005
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<u>Answer</u>
0
<u>Explanation</u>
(2m)/(2m+3)-(2m)/(2m-3)=1
Simplifying the left hand first
(2m)/(2m+3)-(2m)/(2m-3) = {2m(2m-3) - 2m(2m+3)}/(4m²-9)
(4m²-6m-4m²-6m)/(4m²-9)
= (-12m) / (4m²-9)
Now this equet to 1
(-12m) / (4m²-9) = 1
-12m = 4m²-9
4m²+ 12m -9 =0 ⇒⇒⇒ This is a quadratic equation that has 2 real solutions.
4m²+ 12m -9 =0
m² + 3m + (3/2)²= 9/4 + 9/4
(m + 3/2)² = 18/4
m = √18/2 - 3/2 or m = -√18/2 - 3/2
= 0.621 = -3.621
So we can say that the equation has NO extraneous solutions.
Answer = 0
Answer:
Step-by-step explanation:
Base on my own understanding what should be done is that three stacks will not work, because it wont be a symmetric arrangement and also one will be left out. So, two stacks of five each would be better and easy to carry. But the stacks should be arranged in such a manner that the lengths will be parallel to each other and not in-line which would increase the length making it comparatively very long. its easier to hold a (2*8.5,11,2*5=17,11,17) compact box, because it will be easy to carry a long and not heavy.
