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2 years ago

Price is frequently only way to attract consumers to store when merchandise products are comparable. True False

Mathematics

1 answer:

Helga [31]2 years ago

3 0

Answer: True

Explanation:

Yes, this is true that price is the only way to attract the customers to store when merchandise products are comparable as, price is the main key factor for attracted the customers by the factor like sales and discounts. The main purpose for each retailer is that selling there products with good price and attracted the customers by the price and the quality of the product.

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In △ ABC and △DEF, AC = DF, AB = DE and < A = <br><br> Pls help dont scam me pls....

zysi [14]

Answer:

∠A = ∠D (**but very important Δ ABC has to be congruent to Δ DEF)

Step-by-step explanation:

It will help if you draw the triangles out and label the same sides. Then according to the side-angle-side (SAS) rule, ∠A should be equal to ∠D

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2 years ago

If 4x+3x-2(x+5)=-9 then x=?

Nana76 [90]

Answer:

X=1/5

Step-by-step explanation:

7×-2×-10=-9

5×=-9 +10

5×/5=1/5

×=1/5

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2 years ago

Calculate 0.82 + 0.35 and get the sum of the equation

xz_007 [3.2K]

1.17

because

0.82

0.35 +

---------

1.17

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2 years ago

A $40.00 skateboard is discounted 30%. If sales tax is 5%, what is the amount of tax paid?

tekilochka [14]

$29.40 ........ 40x0.3=12....... 40-12=28...... 28x1.05= $29.40

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2 years ago

Read 2 more answers

A large operator of timeshare complexes requires anyone interested in making a purchase to first visit the site of interest. His

morpeh [17]

Answer:

There is a 21.053% probability that this person made a day visit.

There is a 39.474% probability that this person made a one night visit.

There is a 39.474% probability that this person made a two night visit.

Step-by-step explanation:

We have these following percentages

20% select a day visit

50% select a one-night visit

30% select a two-night visit

40% of the day visitors make a purchase

30% of one night visitors make a purchase

50% of two night visitors make a purchase

The first step to solve this problem is finding the probability that a randomly selected visitor makes a purchase. So:

$P = 0.2(0.4) + 0.5(0.3) + 0.3(0.5) = 0.38$

There is a 38% probability that a randomly selected visitor makes a purchase.

Now, as for the questions, we can formulate them as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Suppose a visitor is randomly selected and is found to have made a purchase.

How likely is it that this person made a day visit?

What is the probability that this person made a day visit, given that she made a purchase?

P(B) is the probability that the person made a day visit. So $P(B) = 0.20$

P(A/B) is the probability that the person who made a day visit made a purchase. So $P(A/B) = 0.4$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.4*0.2}{0.38} = 0.21053$

There is a 21.053% probability that this person made a day visit.

How likely is it that this person made a one-night visit?

What is the probability that this person made a one night visit, given that she made a purchase?

P(B) is the probability that the person made a one night visit. So $P(B) = 0.50$

P(A/B) is the probability that the person who made a one night visit made a purchase. So $P(A/B) = 0.3$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.3}{0.38} = 0.39474$

There is a 39.474% probability that this person made a one night visit.

How likely is it that this person made a two-night visit?

What is the probability that this person made a two night visit, given that she made a purchase?

P(B) is the probability that the person made a two night visit. So $P(B) = 0.30$

P(A/B) is the probability that the person who made a two night visit made a purchase. So $P(A/B) = 0.5$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.5}{0.38} = 0.39474$

There is a 39.474% probability that this person made a two night visit.

3 0

2 years ago