Answer:
APBCD
Step-by-step explanation:
Because this make sance
According to the probles represented above, there is addition of two angles which makes it totally clear. I am pretty sure that the answer with the actual reason of this task is the second option <span>B. Angle Addition Postulate, as you can see a couple of new angles in there :)
Regards!</span>
Answer:
first option
Step-by-step explanation:
Given
f(x) = 
← factorise the numerator
= 
← cancel (x + 4) on numerator/ denominator
= 2x - 3
Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is
x = - 4
Substitute x = - 4 into the simplified f(x) for y- coordinate
f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11
The discontinuity occurs at (- 4, - 11 )
To obtain the zero let f(x) = 0, that is
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = 
There is a zero at ( , 0 )
Thus
discontinuity at (- 4, - 11 ), zero at ( , 0 )
Let no be x
Acc to ques
X + 2(1/x) = 3
X + 2/x = 3
X^2 + 2 = 3x
X^2 - 3x + 2 = 0
X^2 - x - 2x + 2 = 0
X (x-1) - 2 (x-1) = 0
(x-2) (x-1) = 0
X= 2 or x =1
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