Answer:
c
Explanation:
I hope this may help you guys
18)
a. Ra
d. Ag
19)
a. C
b. Br
c. Mg
20)
a. S
b. Br
c. O
Sorry wasn’t sure about some of them in #18
Hope the notes are helpful.
Iodine is decolorized.
The first reaction stated in the question occurs as follows;
2 KI (aq) + 2 H2SO4 (aq) + MnO2 (s) → MnSO4 (aq) + K2SO4 (aq) + I2 (s) + 2 H2O (l)
The reaction here is the formation of iodine from MnO2 and KI in the presence of dropwise H2SO4.
Hypo is the common name of sodium thio-sulphate or sodium hypo-sulfite.
The equation of the titration reaction is;
2Na2S2O3 + I2→ Na2S4O6 + 2NaI
When this reaction takes place, iodine is decolorized due to its reduction to I^-.
Answer:
Solution given:
heat[Q]=?
temperature [T]=0.64°C
specific heat capacity [c]=0.880 J/g °C
mass[m]=3g
we have
Q=mcT=3*0.880*0.64°=1.69Joule
<u>the</u><u> </u><u>required</u><u> heat </u><u>is</u><u> </u><u>1.69</u><u>Joule</u><u>.</u>
Answer: 14.625g
Explanation:
No of moles= mass given/molar mass
No of moles given= 0.375mol
Mass is the unknown (?)
Molar mass of K= 39
No of moles = mass given/molar mass
Substitute the values
0.375= mass/39
Cross multiply
Mass = 39×0.375
Mass= 14.625g
The mass is 14.625g