Answer:
F=10.2N : Force with which the player must push the disc
Explanation:
Conceptual analysis
We apply Newton's first law because the speed is constant in horizontal direction (x):
∑Fx = 0 Formula (1)
We apply Newton's first law because the speed is zero in vertical direction (y):
∑Fy= 0 Formula (2)
∑F: algebraic sum of forces in Newton (N)
We calculate the friction force with the following formula:
Ff=f*N Formula (3)
Ff= friction force in Newtons (N)
f = coefficient of friction
N= Normal force in Newtons (N)
Known data:
Wp = 170 N : puck weight
f = 0.0600 :coefficient of friction
Problem development
We replace the data in formula (1) and (2), considering that the force is positive (+) if it goes in the direction of the movement and negative (-) if it opposes the movement:
∑Fy= 0
N-Wp=0
N= Wp=170 N
∑Fx =0
F - Ff=0 F :force with which the player must push the disc
F - 0.0600*170 =0
F=10.2N
