Answer:
Missing x:0
Missing y:1
Hence, option b is correct.
Step-by-step explanation:
Given the table
x y
-9 3
-6 2
-3 missing
missing 0
As we know that the linear function has a constant common difference between the x values and y values.
From the table, it is clear that the x values have the same common difference, and the consecutive x values are separated by -3.
i.e. -9-(-6)=-3
-6-(-3)=-3
So the missing x value will be:
-3-(x)=-3
-3-(0)=-3
Therefore, the missing x value wil be: 0
From the table, it is clear that the x values have the same common difference, and the consecutive x values are separated by 1.
i.e.
3-2=1
2-y=1
y=1
Therefore, the missing y-value will be 1.
Therefore,
Missing x:0
Missing y:1
Hence, option b is correct.
Answer:
x = 5
Step-by-step explanation:
5 times 5 = 25
25 times 5 = 125
125 times 5 = 625
625 times 5 = 3125
There are five fives.
x = 5
<h3>
Answer: 1/4</h3>
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Explanation:
Let's say there are 60 members at the club. I picked this value since 10*6 = 60, which is the product of the denominators. This will help give us whole numbers in the steps shown below. You can pick any number you want for the club size.
Since we have 60 members and 3/10 of them are men, this means (3/10)*60 = 18.
So there are 18 men at this club.
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Next, we're told that 5/6 of the men are right handed. So (5/6)*18 = 15 men are right handed.
Lastly, we divide that last result (15) over the total number of club members (60) and we end up with 15/60 = (1*15)/(4*15) = 1/4
Therefore, 1/4 of the members are men who are right handed.
Unfortunately, we don't have enough data to be able to say anything about what fraction of the women are right handed.
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Note that:
(3/10)*(5/6) = (3*5)/(10*6) = 15/60 = 1/4
which is an alternative pathway to the solution.
1 inch = 5 yards that’s the awnser
Answer:
33,856 passwords can be created using this format
Step-by-step explanation:
Since the letters and the digits can be repeated, for each letter there are 23 possible outcomes and for each digit there are 8 possible outcomes.
There are 2 letters and then 2 digits in the password. So
23*23*8*8 = 33,856
33,856 passwords can be created using this format