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2 years ago

BaCl2(aq) + Na2SO4(aq) ⇄ 2NaCl(aq) + BaSO4(s)

Chemistry

1 answer:

sp2606 [1]2 years ago

3 0

Answer:

D) The equilibrium will shift to the right and more precipitate will be formed.

Explanation:

Le Châtelier's principle states that <em>when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium</em>.

For the reaction:

<em>BaCl₂(aq) + Na₂SO₄(aq) ⇄ 2NaCl(aq) + BaSO₄(s)↓</em>,

Adding more <em>BaCl₂ </em>to the system:

will increase the concentration of BaCl₂ (reactants), so the equilibrium will be shifted to the right side (products side) to suppress the effect of increasing the BaCl₂.

So, the right choice is:

<em>D) The equilibrium will shift to the right and more precipitate will be formed.</em>

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EleoNora [17]

I believe pH = -log[H+]

Also, 14 = pH + pOH

Therefore pH = 14 - pOH

pH = 14 - 4.01

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Hope this helps!

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1 year ago

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2 years ago

A bike rider approaches a hill with a speed of 8.5 m/s. The total mass of the bike and the rider is 85 kg. Find the kinetic ener

krek1111 [17]

KE=3070.625 J

Height = 3.686 m

<h3>Further explanation</h3>

mass of bike+rider=85 kg

velocity = 8.5 m/s

$\tt KE=\dfrac{1}{2}mv^2\\\\KE=\dfrac{1}{2}\times 85\times 8.5^2\\\\KE=3070.625~J$

Conservation of energy :

(KE+PE)₁ (downhill) = (KE+PE)₂ (up the hill)

PE₁=0⇒h=0

KE₂=0⇒v=0(stop), so equation becomes :

KE₁=PE₂

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2 years ago