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2 years ago

Factorise(x + 2)^2 + p^2 + 2p (x + 2)

Mathematics

1 answer:

Sveta_85 [38]2 years ago

8 0

Answer:

( x +2 +p) ( x+2+p)

Step-by-step explanation:

let x+2 be x

x^2 + p^2 + 2px

x^2 + 2 × p × x + p^2

(x+p)^2

(x+p)(x+p)

replacing the value of x

( x +2 +p) ( x+2+p)

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PLEASE HELP mathematics

AlexFokin [52]

Answer:

21+10.5 which would equal 31.5

Step-by-step explanation:

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2 years ago

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What is 3k +2 ( 5k - 3) = 7

polet [3.4K]

Answer:

k= -0.2

Step-by-step explanation:

3+2(5k-3)=7 (original)

3+10k-6=7 (distribute 2 in (5k-3))

9+10k=7 (combine like terms 3+-6)

10k=-2 (subtract 9 on both sides to isolate k)

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2 years ago

Help please! Ty!! ----

Tresset [83]

Answer:

5 4/9

Step-by-step explanation:

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2 years ago

Write an inequality for the given statement: The sum of x and 25 is less than 75.

Kaylis [27]

That statement would be best express by " x + 25 < 75 ". Since the statement says the sum of x and 25, thus, it will be x + 25. Then it also states that the sum is less than 75, so the best expression would be " < 75".

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2 years ago

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

2 years ago

Factorise(x + 2)^2 + p^2 + 2p (x + 2)​

Factorise(x + 2)^2 + p^2 + 2p (x + 2)