X = jane, y = jasmine, z = jocelyn
x + y + z = 56
x = 3z
y = 2z + 2
3z + 2z + 2 + z = 56
6z + 2 = 56
6z = 56 - 2
6z = 54
z = 54/6
z = 9 <==== jocelyn
x = 3z
x = 3(9)
x = 27 <=== jane
y = 2z + 2
y = 2(9) + 2
y = 18 + 2
y = 20 <=== jasmine
Answer:
s=10
Step-by-step explanation:
Basically, the range rule-of-thumb is that the range is generally about four times the standard deviation.
<u>First, we find the range:</u>
Range=Maximum-Minimum
Range=100-60
Range=40
<u>Next, divide the range by 4 to get the standard deviation</u>
Range=4(Standard Deviation)
40=4(Standard Deviation)
10=Standard Deviation
Therefore, s=10, which is the standard deviation
Answer:
<h2> Hey, Option C is correct.....</h2>
1 3/4 - 5/6r = 8/3
-5/6r + 7/4 = 8/3
-5/6r +7/4 - 7/4 = 8/3 -7/4
-5/6r = 11/12
(6/-5)*(-5/6r)=(6/-5)*(11/12)
=-11/10
r = -1 1/10
