All categories

3 years ago

HELP PLEASE I WILL GIVE 13 POINTS

Mathematics

1 answer:

kenny6666 [7]3 years ago

3 0

Answer:

this difference indicates that the results are independent but not reliable.

You might be interested in

Write 3x^2-18x-6 in vertex form

Vedmedyk [2.9K]

The standard form of a quadratic equation is $\displaystyle{ y=ax^2+bx+c$ , while the vertex form is:

$y=a(x-h)^2+k$ , where (h, k) is the vertex of the parabola.

What we want is to write $\displaystyle{ y=3x^2-18x-6$ as $y=a(x-h)^2+k$

First, we note that all the three terms have a factor of 3, so we factorize it and write:

$\displaystyle{ y=3(x^2-6x-2)$ .

Second, we notice that $x^2-6x$ are the terms produced by $(x-3)^2=x^2-6x+9$ , without the 9. So we can write:

$x^2-6x=(x-3)^2-9$ , and substituting in $\displaystyle{ y=3(x^2-6x-2)$ we have:

$\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]$ .

Finally, distributing 3 over the two terms in the brackets we have:

$y=3[x-3]^2-33$ .

Answer: $y=3(x-3)^2-33$

6 0

2 years ago

Which is one of the transformations applied to the graph of f(x) = x2 to change it into the graph of g(x) = 9x? – 36X?

matrenka [14]

Answer: C. The graph of f(x)= x2 is shifted down 36 units

Step-by-step explanation:

6 0

2 years ago

What is the velocity of a bird with a mass of 2 kilograms flying at 60 kg*m/s?

scoundrel [369]

Answer:

30 m/s

Step-by-step explanation:

p = mv

momentum = mass × velocity

here the momentum is 60kgm/s

mass is 2kg

substitute in the equation

60 = 2v

v= 30m/s

4 0

3 years ago

The fraction 4/3 is equivalent to A: 3/4 B: 5/4 C: 1 1/3 D: 4 1/3

ra1l [238]

Using the denominator of 3 we know 3/3 would be equal to 1

Subtract 3/3 from 4/3 = 1/3

So 4/3 = 1 and 1/3

The answer is c.

3 0

2 years ago

The side length of each square is 6 units. Find the areas of the inscribed shapes.

kirill [66]

By using subtraction of yellow areas from the entire squares, the areas of the inscribed shapes are listed below:

18 units
20 units
12 units
12 units

<h3>How to calculate the areas of the inscribed shapes</h3>

The areas of the inscribed shapes can be easily found by subtracting the yellow areas from the square, in order to find the value of green areas. Now we proceed to find the result for each case by using area formulae for triangles:

Case A

A = 6² - 0.5 · (3) · (6) - 0.5 · (3) · (6)

A = 36 - 18

A = 18 units

Case B

A = 6² - 4 · 0.5 · (2) · (4)

A = 36 - 16

A = 20 units

Case C

A = 6² - 0.5 · 6² - 0.5 · 6 · 2

A = 36 - 18 - 6

A = 12 units

Case D

A = 6² - 2 · 0.5 · 6 · 4

A = 36 - 24

A = 12 units

To learn more on inscribed areas: brainly.com/question/22964077

#SPJ1

4 0

1 year ago