All categories

2 years ago

9. What is the system of equations that describes the following graph?

Mathematics

1 answer:

jeka942 years ago

3 0

The graph represented in the figure shows a set of linear equations each of which is represented a straight line.

Step-by-step explanation:

System of Equation can be referred to as an assortment of equations to be dealt with. Common examples include linear equations and non-linear equations such as a parabola, hyperbola etc.

Linear set of equations are the most simple of equation depicting a linear relationship between two variables.

E.g. Y=4x+3

here y and x share a linear relationship which is defined by the straight-line graph "4x+3"

Similarly in the graph lines, two straight lines are depicted which symbolises that the et of the equation is linear in character.

You might be interested in

What is the degree of polynomial 2x^7+4-5x^8-4x

MAVERICK [17]

Answer:

Step-by-step explanation:

7+8

7 0

2 years ago

How do you tell if a graph is a function

miss Akunina [59]

Take a vertical line and place it on thegraph. If the graph is a function, then no matter where on the graph you place the vertical line, the graphshould only cross the vertical line once.

4 0

2 years ago

Read 2 more answers

I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5

Gnesinka [82]

Given:
$f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}$

Using
$\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}$
we derive
$\frac{d}{dx}4xcos^{-1}(2x+4)$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}$

Similarly, using
$\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}$
we derive
$\frac{d}{dx}(-\sqrt{3-3x^2})$
$=\frac{3x}{\sqrt{3-3x^2}}$

Therefore, the derivative is
$f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}$

3 0

2 years ago

Read 2 more answers

What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)?

Monica [59]

Answer:

y = 4x + 16

Step-by-step explanation:

y - 1 = 4(x + 3)

Has a slope of 4

y = 4x + c

32 = 4(4) + c

32 - 16 = c

c = 16

y = 4x + 16

7 0

2 years ago

Read 2 more answers

Historically, a certain region has experienced 92 thunder days annually. (A "thunder day" is day on which at least one instance

DiKsa [7]

Answer:

We conclude that the mean number of thunder days is less than 92.

Step-by-step explanation:

We are given that Historically, a certain region has experienced 92 thunder days annually.

Over the past fifteen years, the mean number of thunder days is 72 with a standard deviation of 38.

Let $\mu$ = mean number of thunder days.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 92 days {means that the mean number of thunder days is more than or equal to 92}

Alternate Hypothesis, $H_A$ : $\mu$ < 92 days {means that the mean number of thunder days is less than 92}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean number of thunder days = 72

s = sample standard deviation = 38

n = sample of years = 15

So, test statistics = $\frac{72-92}{\frac{38}{\sqrt{15} } }$ ~ $t_1_4$

= -2.038

The value of z test statistics is -2.038.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical value of -1.761 at 14 degree of freedom for left-tailed test.

Since our test statistics is less than the critical value of t as -2.038 < -1.761, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean number of thunder days is less than 92.

7 0

2 years ago