Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer: 9/20
Step-by-step explanation:
From the question, we are informed that Tyce hit 3/5 of the baseballs pitched to him during batting practice and that Mason hit 3/4 of the number of the pitched that tyce hit.
The fraction of pitches that Mason hit will be gotten by multiplying 3/4 by 3/5 This will be:
= 3/4 × 3/5
= 9/20
answer: you're missing the problem
the diamiter is the two out side numbers minused by 3.14
Perimeter is adding up all the dues together
if it’s 30
13+5=18
30-18=12
x is 12