To solve the problem we could separate the figure into three parts. First figure is a triangle, second figure is a rectangle, third figure is a triangle. See image attached.
Solve each area of the figuresFirst figure, a triangle that have 7 units long of the base, and 2 units long of the height.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the first figure is 7 units²
Second figure is a rectangle, the length of the rectangle is 7 units, the width of the rectangle is 4 units.
a = l × w
a = 7 × 4
a = 28
The area of the second figure is 28 units²
Third figure is a triangle, the base is 7 units long and the height is 2 units long.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the third figure is 7 units²
The area of the three figuresarea = first figure area + second figure area + third figure area
area = 7 + 28 + 7
area = 42
The total area of the figures is 42 units²
Answer:
47
Step-by-step explanation:
Let a, b, and c be those three numbers.
When two of the three numbers are added at a time, the possible sums are 32, 39, 23. Let
Add these three equations:
Divide this equation by 2:
The sum of all three numbers is 47.
Is there supposed to be a graph or another picture? I do not see anything.
It would be x + 1 under the absolute value
Answer:
The total number of marbles in the bag is 50.
Step-by-step explanation:
Here, we have n trials, without replacement. So the hypergeometric distribution is used.
The mean of the hypergeometric distribution is:
In which n is the number of items in the sample, k is the number of items in the population that are classified a success and N is the size of the population.
15 marbles are drawn:
This means that
A bag contains some number of marbles. It is known that 20 of them are red.
This means that , since a success is drawing a red marble.
Assuming E(X)=6 red, what is the total number of marbles in the bag?
We have to find N when
So
The total number of marbles in the bag is 50.