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2 years ago

CILJUCCO

Chemistry

1 answer:

maria [59]2 years ago

3 0

C. The expectations of the participants

Explanation:

The expectations of participants results in the placebo and nacebo effects. Usually, subjects in an experiment expect a certain type of outcome in their research process and this leads to the the placebo effects.

Placebos are inert drugs with no therapeutic values.
Nacebo effects arise from the negative expectations of subject which causes a sort of perceived harm.
Participant expects a certain type of result from drug usage and their reactions can be skewed by this expectation.

Learn more:

something on experiments brainly.com/question/8203464

placebo brainly.com/question/12988866

#learnwithBrainly

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Describe are seasons like near the equator.

adell [148]

Answer:

Hi! Think of it like this:

You and your family are going to go on a vaction for the holidays, to south america or somewhere else. You´re near the equator so it will be warm. If you were to move there, you might pull out the swimsiutes because most of the time, its useally warm and sunny. They dont really get cold weather. They will have a nice and warm christmas.

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2 years ago

A technician measures the weight of a reagent . The weight is 3269 g. What is the weight in kilograms ? Write your answer as a d

Georgia [21]

Answer:

3.269 kg

Explanation:

1000g = 1 kg. Since kg is the larger unit, you need to divide by 1000 to get kilograms. You can do the problem as a unit conversion:

3269 g × <u>1 kg</u> = 3.269 kg

1000g

Hope this is helpful!

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2 years ago

Scientists us ________waves to study the characteristics of Earth Layers_______ cannot travel through liquid, so the ________mus

Lady bird [3.3K]

Answer:

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2 years ago

If the molar heat of combustion of liquid benzene at constant volume and 300k is -3272KJ. Calculate the heat of combustion at co

vladimir2022 [97]

Answer:

The heat at constant pressure is -3,275.7413 kJ

Explanation:

The combustion equation is 2C₆H₆ (l) + 15O₂ (g) → 12CO₂ (g) + 6H₂O (l)

$\Delta n_g$ = (12 - 15)/2 = -3/2

We have;

$\Delta H = \Delta U + \Delta n_g\cdot R\cdot T$

Where R and T are constant, and ΔU is given we can write the relationship as follows;

$H = U + \Delta n_g\cdot R\cdot T$

Where;

H = The heat at constant pressure

U = The heat at constant volume = -3,272 kJ

$\Delta n_g$ = The change in the number of gas molecules per mole

R = The universal gas constant = 8.314 J/(mol·K)

T = The temperature = 300 K

Therefore, we get;

H = -3,272 kJ + (-3/2) mol ×8.314 J/(mol·K) ×300 K) × 1 kJ/(1000 J) = -3,275.7413 kJ

The heat at constant pressure, H = -3,275.7413 kJ.

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2 years ago

Please if anyone know this question, tell me its answer. I will be very thankful to you<br>

Verizon [17]

Ch-c§c will get the answer

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1 year ago