9.1/3575
use long division like this
_<u>0.</u>_________
3575|91.000000
we find how many of 3575 fit into the 91
it's too big so we go farther
how many 3575 go into 910
too big so we go farther
how many 3575 go into 9100
the answer is 2 so put that in the correct place and mulitply that and put that in the correct place. then we subtract
_<u>0.</u><u>02</u>_________
3575|91.000000
-<u>71.50</u>
19.50
bring down the next number
find how many go into 19.500
the answe ris 5
_<u>0.</u><u>02</u><u>5</u>_________
3575|91.000000
-<u>71.50</u>
19.500
-<u>17.875</u>
1.625
bring down he next zero ( I fast forward and skip steps for convinience)
__
_<u>0.</u><u>02</u><u>5</u><u>455</u>_________
3575|91.000000
-<u>71.50</u>
19.500
-<u>17.875</u>
1.6250
-<u>1.4300</u>
.19500
-<u>.17875
</u> 16250
-14300
and so on untill infinity so the answe ris 0.0254555555555555 (enless fives)
Answer:
= 384
Step-by-step explanation:
(-8)(-4)(12)
= (32)(12)
=384
Answer:
P(a junior or a senior)=1
Step-by-step explanation:
The formula of the probability is given by:
Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.
In this case, N is the total number of the students of statistics class.
N=18+10=28
The probability of the union of two mutually exclusive events is given by:
Therefore:
P(a junior or a senior) =P(a junior)+P(a senior)
Because a student is a junior or a senior, not both.
n(a junior)=18
n(a senior)=10
P(a junior)=18/28
P(a senior) = 10/28
P(a junior or a senior) = 18/28 + 10/28
Solving the sum of the fractions:
P(a junior or a senior) = 28/28 = 1
Answer:
This is a function and it's because there's only one input for every output.
Step-by-step explanation:
Note: Although 5 and 1 both point to the same number this doesn't take away the validity of the function. :)