Answer:
= 4.86 s
= 1.98 s
Explanation:
<u><em>Given:</em></u>
Length = l = 1 m
Acceleration due to gravity of moon = = 1.67 m/s²
Acceleration due to gravity of Earth = = 10 m/s²
<u><em>Required:</em></u>
Time period = T = ?
<u><em>Formula:</em></u>
T = 2π
<u><em>Solution:</em></u>
<u>For moon</u>
<em>Putting the givens,</em>
T = 2(3.14)
T = 6.3
T = 6.3 × 0.77
T = 4.86 sec
<u>For Earth,</u>
<em>Putting the givens</em>
T = 2π
T = 2(3.14)
T = 6.3 × 0.32
T = 1.98 sec
Answer
Ceres, Pluto, and Eris are classified as DWARF PLANET.
A) Leftover planetesimals inside the frost line are known as ASTEROIDS.
B) METEORITES are the pieces of Asteroids which are fallen on the earth's surface.
C) COMETS are the objects which are visible with long tails.
D) COMETS are also the leftover planetesimals that are occupied by the jovian planets and are formed in the solar system.
E) Meteor showers are associated with debris from COMETS
Answer:
Explanation:
From the question;
We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.
We are to calculate the following task, i.e. to determine the electric field at the distances:
a) at 4.75 cm
b) at 20.5 cm
c) at 125.0 cm
Given that:
the charge (q) = 33.3 nC/m
= 33.3 × 10⁻⁹ c/m
radius of rod = 5.75 cm
a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.
Then, the electric field will be zero.
b) The electric field formula
E = 1461.95 N/C
c) The electric field E is calculated as:
E = 239.76 N/C
Answer:
B. Solids, liquids, and gases.
Explanation:
I have no explanation.
Answer:
1.549 m
Explanation:
Given:
The radius of the circular board, r = 2 m
The probability of hitting the red is given as 0.6
Now, this probability of hitting the red can be conclude as
0.6 = (Area of red)/ (Total area of the board)
Total area of the board = πr² = π × 2²
let the radius of the red area be R
thus, area of red circle, = πR²
on substituting the value of the area, we have
0.6 = (πR²)/ (π × 2²)
or
R² = 2.4
or
R = 1.549 m
Thus, the radius of the red circle is 1.549 m