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2 years ago

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Mathematics

1 answer:

Readme [11.4K]2 years ago

6 0

Answer:

1) y= 2x-4

2) y= 2/3 - 3

3) y=1/2x+2

4) y=-4x-4

Step-by-step explanation:

all you basically has to do is is subtract the x to isolate the y and if the y and if the y still has a number by it you use it to decide it

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(Picture) MULTIPLYING MONOMIALS AND BINOMIALS

Contact [7]

Answer:

Third and sixt option

Step-by-step explanation:

Applying the distributive property:

(b-2c)(-3b+c)=b(-3b)+b(c)-2c(-3b)-2c(c)

(b-2c)(-3b+c)=-3b^2+bc+6bc-2c^2

Adding like terms:

(b-2c)(-3b+c)=-3b^2+7bc-2c^2

The simplified product has 3 terms (first and second option are not true)

The simplified product has a degree of 2 (third option is true)

The simplified product, in standard form, has exactly 2 negative terms: -3b^2 and -2c^2 (sixth option is true)

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2 years ago

(-3,3) 8 units down and 7 units right

Alexus [3.1K]

Answer:

look it up

Step-by-step explanation:

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2 years ago

What is the true solution to the equation below?

Marina CMI [18]

Answer:

The solution is:

$x=4$

Step-by-step explanation:

Considering the expression

$lne^{lnx}+lne^{lnx}^{^2}=2ln8$

$\ln \left(e^{\ln \left(x\right)}\right)+\ln \left(e^{\ln \left(x\right)\cdot \:2}\right)=2\ln \left(8\right)$

$\mathrm{Apply\:log\:rule}:\quad \:log_a\left(a^b\right)=b$

$\ln \left(e^{\ln \left(x\right)}\right)=\ln \left(x\right),\:\space\ln \left(e^{\ln \left(x\right)2}\right)=\ln \left(x\right)2$

$\ln \left(x\right)+\ln \left(x\right)\cdot \:2=2\ln \left(8\right)$

$\mathrm{Add\:similar\:elements:}\:\ln \left(x\right)+2\ln \left(x\right)=3\ln \left(x\right)$

$3\ln \left(x\right)=2\ln \left(8\right)$

$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{3\ln \left(x\right)}{3}=\frac{2\ln \left(8\right)}{3}$

$\ln \left(x\right)=\frac{2\ln \left(8\right)}{3}.....A$

Solving the right side of the equation A.

$\frac{2\ln \left(8\right)}{3}$

$\ln \left(8\right):\quad 3\ln \left(2\right)$

Because

$\ln \left(8\right)$

$\mathrm{Rewrite\:}8\mathrm{\:in\:power-base\:form:}\quad 8=2^3$

⇒ $\ln \left(2^3\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)$

$\ln \left(2^3\right)=3\ln \left(2\right)$

$\frac{2\ln \left(8\right)}{3}=\frac{2\cdot \:3\ln \left(2\right)}{3}$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:3=6$

$=\frac{6\ln \left(2\right)}{3}$

$\mathrm{Divide\:the\:numbers:}\:\frac{6}{3}=2$

$=2\ln \left(2\right)$

So, equation A becomes

$\ln \left(x\right)=2\ln \left(2\right)$

$\mathrm{Apply\:log\:rule}:\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)$

$=\ln \left(2^2\right)$

$=\ln \left(4\right)$

$\ln \left(x\right)=\ln \left(4\right)$

$\mathrm{Apply\:log\:rule:\:\:If}\:\log _b\left(f\left(x\right)\right)=\log _b\left(g\left(x\right)\right)\:\mathrm{then}\:f\left(x\right)=g\left(x\right)$

$x=4$

Therefore, the solution is

$x=4$

6 0

2 years ago

Read 2 more answers

Z1 and Z2 are vertical angles. Z2 has a measure of 31º.<br> What is the measure of Z1

kogti [31]

Answer:

whatever 31-18 is i think

Step-by-step explanation:

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2 years ago

Rearrange the following equation to solve for x. y=1/2x+10

maxonik [38]

In order to solve this we must first,

Subtract both sides of the equation by 10,
y-10=1/2x

Now we have to multiply both sides by 2 so that only x is left.

2y-20=x

Therefore, x=2y-20

6 0

2 years ago