Using the law of sines,
sin80°/3.1 = sin∠QSR/2.4
∠QSR = sin^-1(2.4sin80°/3.1)
≈ 49.679°
∠SQR = 180° - 80° - 49.679° (angles in a triangle)
= 50.321°
sin50.321°/RS = sin80°/3.1
RS = (3.1sin50.321°/sin80°)
= 2.4 units (nearest tenth)
The length of line RS is 2.4 units.
Base = 12÷2
= 6
slant height = a
a^2 = 6^2 + 8^2
a^2 = 100
a = 10 cm
Answer:
I believe its the second one but i could be wrong
Answer:
The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.
Step-by-step explanation:
The average speed is given by the following equation:
From 10A.M. to noon.
You traveled at 50mph during 2 hours. So how long you traveled?
You traveled 100 miles.
What was your average speed over the time interval from 9 A.M. to noon
From 9 A.M. to 10 A.M, you did not travel.
From 10 P.M. to noon, 100 miles.
So 100 miles during 3 hours.
The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.