The surface area of the triangular prism is of 140 cm².
<h3>What is the surface area of a prism?</h3>
It is the sum of the areas of all faces of a prism. In this problem, the prism has these following faces:
- One rectangle of dimensions 8 cm and 6 + 4 + 5 = 15 cm.
- Two right triangles with sides 4 cm and 5 cm.
For a rectangle, the area is given by the multiplication of the dimensions, hence:
Ar = 8 x 15 = 120 cm²
For each right triangle, the area is given by half the multiplication of the sides, hence:
At = 2 x 0.5 x 4 x 5 = 20 cm².
Then the surface area of the prism is:
S = 120 cm² + 20 cm² = 140 cm².
More can be learned about surface area at brainly.com/question/28123954
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Range = max-min= 150-119 = 31
The answer is A, as I calculated the difference using Pythagora's Theorem. Which I then did 7.6-6.3= 1.29122, which rounds to 1.0 cm^2
Answer:
x>7 or x ≤ -3
Step-by-step explanation:
Solving the 1st inequality
-6x +14 < -28 --------------- (Collect like terms)
-6x < -28 - 14
-6x < - 42 -------------------- (Divide both sides by -6)
Note: If you decide an inequality expression by a negative value, the inequality sign changes)
-6x/-6 > -42/-6
x > 7
Solving the 2nd inequality
9x + 15 ≤ −12 ----------- (Collect like terms)
9x ≤ −12 - 15
9x ≤ −27 ------------------(Divide both sides by 9)
9
9x/9 ≤ −27/9
x ≤ -3
Bring both results together, we get
x>7 or x ≤ -3
The final result is complex (i.e. can't be combined together).
