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Answer:
60 N
Explanation:
This is just Newton's Second Law
F = m*a
F = ?
m = 12 kg
a = 5 m/^2
F = 5*12 = 60 Newtons
Kinetic energy = 1/2mv^2
=1/2(25)(1^2)
= 12.5J
Ideal Gas Law PV = nRT
THE GASEOUS STATE
Pressure atm
Volume liters
n moles
R L atm mol^-1 K^-1
Temperature Kelvin
pv = rt
divide both sides by v
pv/v = rt/v
p = rt/v
answer: p = rt/v
Ideal Gas Law: Density
PV = NRT
PV = mass/(mw)RT
mass/V = P (MW)/RT = density
Molar Mass:
Ideal Gas Law PV = NRT
PV = mass/(MW) RT
MW = mass * RT/PV
Measures of Gases:
Daltons Law of Partial Pressures; is the total pressure of a mixture of gases equals the sum of the partial pressures of the individual gases.
Total = P_ A + P_ B
P_ A V = n_ A RT
P_ B V = n_ B R T
Partial Pressures in Gas Mixtures:
P_ total = P_ A + P_ B
P_ A = n_ A RT/V P_ B = n_ B RTV
P_ total = P_ A + P_ B = n_ total RT/V
For Ideal Gasses:
P_ A = n_ A RT/V P_ total = n_ toatal RT/V
P_ A/P_ total = n_ A RTV/n_ total RTV
= n_ A/n_ total = X_ A
Therefore, P_ A = X_ A P_ total.
PV = nRT
P pressure
V volume
n Number of moles
R Gas Constant
T temperture (Kelvin.).
Hope that helps!!!!!! Have a great day : )
Answer:
It is sensible heat- the amount of heat absorbed by 1 kg of water when heated at a constant pressure from freezing point 0 degree Celsius to the temperature of formation of steam i.e. saturation temperature
So it is given as - mass× specific heat × rise in temperature
i.e. 4.2 × T
4.2 × (100–0)
So it is 420kj
If you ask how much quantity of heat is required to convert 1 kg of ice into vapour then you have to add latent heat of fusion that is 336 kj/kg and latent heat of vaporization 2257 kj/kg (these two process occur at constant temperature so need to add rise in tempeature)
So it will be
Q= 1×336 + 1× 4.18 ×100 + 1× 2257
Q = 3011 kj
Or 3.1 Mj
Hope you got this!!!!!!
