<span>speed = wavelength x frequency
speed = 0.4m X 10 Hz
speed = 4 m/s</span>
Answer:
ΔU = 5.21 × 10^(10) J
Explanation:
We are given;
Mass of object; m = 1040 kg
To solve this, we will use the formula for potential energy which is;
U = -GMm/r
But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.
Thus;
ΔU = -GMm((1/r_f) - (1/r_i))
Where;
M is mass of earth = 5.98 × 10^(24) kg
r_f is final radius
r_i is initial radius
G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²
Since, it's moving to altitude four times the Earth's radius, it means that;
r_i = R_e
r_f = R_e + 4R_e = 5R_e
Where R_e is radius of earth = 6371 × 10³ m
Thus;
ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)
× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))
ΔU = 5.21 × 10^(10) J
Answer:
La carrera es importante para ganarse la vida, el respeto en la sociedad y cumplir el sueño.
Explanation:
La carrera es importante por las siguientes razones principales
a) Es una forma de ganar para alimentarse a sí mismo y a su familia y asegurar su futuro.
b) Permite ser considerado como una persona respetable en la sociedad.
c) Es importante ya que también brinda la oportunidad de cumplir el sueño.
Answer:
d= 64.7 km
displacement vector
Explanation:
total distance = 40 + 30 = 70 km
during 1st flight
during 2nd flight
the two component of r are:
Geographical Direction ![\theta = tan^{-1}\frac{r_y}{r_x} [tex]\theta = 40.9^{o}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%5E%7B-1%7D%5Cfrac%7Br_y%7D%7Br_x%7D%20%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Ctheta%20%3D%2040.9%5E%7Bo%7D)
Displacement d
d= 64.7 km
displacement vector
Answer:
A: They produce a real image.
Explanation:
The images formed on the retina of the eye for a normal visibility must always be real.
Only a real image can be physically projected on any physical object whereas the virtual images are visible due to reflections.
- The nearsightedness is corrected with the help of a concave lens since it is the condition of the eye lens remaining thick and curved to converge the rays entering the eyes after a shorter distance which results in their image formation even before the retinal surface so to initially diverge them a bit so that they converge on the retinal surface and form the image there we use concave lens. Vice-versa of the above justification in the case of farsightedness.
