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2 years ago

What is an elastic collision?

Physics

1 answer:

Anit [1.1K]2 years ago

6 0

Answer:

A collision in which both total momentum and total kinetic energy are conserved

Explanation:

In classical physics, we have two types of collisions:

- Elastic collision: elastic collision is a collision in which both the total momentum of the objects involved and the total kinetic energy of the objects involved are conserved

- Inelastic collision: in an inelastic collision, the total momentum of the objects involved is conserved, while the total kinetic energy is not. In this type of collisions, part of the total kinetic energy is converted into heat or other forms of energy due to the presence of frictional forces. When the objects stick together after the collision, the collisions is called 'perfectly inelastic collision'

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A substance has a vapor pressure of 77.86 mm Hg at 318.3 K and a vapor pressure of161.3 mmHg at 340. 7 K. Calculate its heat of

zavuch27 [327]

Explanation:

It is given that,

Initial vapor pressure, P₁ = 77.86 mm

Initial temperature, T₁ = 318.3 K

Final vapor pressure, P₂ = 161.3 mm

Initial temperature, T₂ = 340.7 K

We need to find its heat of vaporization. It can be calculated by using Clausius-Clapeyron equation.

$ln(\dfrac{P_2}{P_1})=\dfrac{\Delta_{vap}H}{R}(\dfrac{1}{T_1}-\dfrac{1}{T_2})$

$\Delta _{vap} H=\dfrac{R\ ln(\dfrac{P_2}{P_1})}{(\dfrac{1}{T_1}-\dfrac{1}{T_2})}$

$\Delta _{vap} H=\dfrac{0.008 314\ ln(\dfrac{161.3}{77.86})}{(\dfrac{1}{318.3}-\dfrac{1}{340.7})}$

$\Delta _{vap} H=29.31\ kJ/mol$

So, the heat of vaporization of a substance is 29.31 kJ/mol. Hence, this is the required solution.

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2 years ago

An atom has a charge of 1+. If the atoms nucleus caintains 23 protons, the atom must have how many electrons

Dmitry [639]

If your atom has a charge of +1, it means you have 1 more proton than electrons. This is because protons have a positive charge and electrons have a negative charge. Because you have 23 protons, and a charge of +1, you have 22 electrons.

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2 years ago

Topic: Chapter 10: Projectory or trajectile?

Charra [1.4K]

Answer:

The other angle is 75⁰

Explanation:

Given;

velocity of the projectile, v = 10 m/s

range of the projectile, R = 5.1 m

angle of projection, 15⁰

The range of a projectile is given as;

$R = \frac{u^2sin(2\theta)}{g}$

To find another angle of projection to give the same range;

$5.1 = \frac{10^2 sin(2\theta)}{9.81} \\\\100sin(2\theta) = 50\\\\sin(2\theta) = 0.5\\\\2\theta = sin^{-1}(0.5)\\\\2\theta = 30^0\\\\\theta = 15^0\\\\since \ the \ angle \ occurs \ in \ \ the \ first \ quadrant,\ the \ equivalent \ angle \\ is \ calculated \ as;\\\\90- \theta = 15^0\\\\\theta = 90 - 15^0\\\\\theta = 75^0$

<u>Check: </u>

sin(2θ) = sin(2 x 75) = sin(150) = 0.5

sin(2θ) = sin(2 x 15) = sin(30) = 0.5

5 0

2 years ago

During light activity, a 70-kg person may generate 200 kcal

Lerok [7]

Answer:

$2.75387\ ^{\circ}$

Explanation:

m = Mass of person = 70 kg

c = Specific heat of human body = $0.83\ J/kg^{\circ}C$

$\Delta T$ = Change in temperature

Time taken is 1 hour

Heat is given by

$Q=mc\Delta T\\\Rightarrow \Delta T=\dfrac{Q}{mc}\\\Rightarrow \Delta T=\dfrac{0.8\times 200\times 1}{70\times 0.83}\\\Rightarrow \Delta T=2.75387\ ^{\circ}C$

The rise in temperature is $2.75387\ ^{\circ}C$

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3 years ago

In which year was the first Badminton game played in the Olympics

Kisachek [45]

Year 1972
if I'm not wrong :)

4 0

2 years ago

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