The arc angle AC is measured as 55 degrees.
<h3>How to find arc angle?</h3>
If two secant intersect in the exterior of a circle, then the measure of the angle formed is half the positive difference of the arcs intercepted.
Therefore, the secants intersect outside the circle at point E.
The arc angle AC can be found as follows:
Therefore,
m∠BED = 1 / 2 (arc angle AC - arc angle BD)
arc angle AC = x
arc angle BD = 23 degrees.
m∠BED = 16 degrees.
m∠BED = 1 / 2 (arc angle AC - arc angle BD)
16 = 1 / 2 (x - 23)
16 = 1 / 2x - 23 / 2
16 + 11.5 = 0.5x
27.5 = 0.5x
x = 27.5 / 0.5
x = 55 degrees.
Therefore,
arc angle AC = 55 degrees.
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Answer:
72
Step-by-step explanation:
because when you do 55% out of 160 it will give you 88 which you subtract from 160 and then you will end up with 72
Hi!
The answer is -15n-10p-5q
Answer:
(8, 5) (Answer C)
Step-by-step explanation:
Write this system of linear equations in a (vertical) column:
4x - 3y = 17
5x + 4y = 60
Let's eliminate y through addition/subtraction:
Multiply 4x - 3y = 17 by 4, obtaining 16x - 12y = 68, and
multiply 5x + 4y = 60 by 3, obtaining 15x + 12y = 180. Then we have:
16x - 12y = 68
15x + 12y = 180
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31x = 248, and so x = 248/31 = 8.
Now find y. Substitute 8 for x in 5x + 4y = 60: 5(8) + 4y = 60, or
4y = 60 - 40 = 20.
Thus, y = 20/4, or y = 5.
The solution is (8, 5) (Answer C)