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2 years ago

The restaurant bill for Annette is $55.82.

1 answer:

5 0

First we have to find 18% of $55.82, which we can do by using the equation 55.82 x 0.18

55.82 x 0.18 = 10.05

so the tip = $10.05

now we just add it to the original bill
55.82 + 10.05 = 65.87

so the total cost = $65.87

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Find the derivative u(x)=4\3x-1

amid [387]

The answer is X=3/4.

6 0

3 years ago

Read 2 more answers

Which graph shows the following system of equations and its solutions? -0.1x-0.3y=1.2 and 0.2x-0.5y=2

Vera_Pavlovna [14]

Answer:

Option b is the correct answer as both the equations are true for given solution.

Step-by-step explanation:

Given equations are:

-0.1x-0.3y=1.2

0.2x-0.5y=2

We can observe each graph and find the point that is the solution and put the point in the equations to know if that point is the solution

For option A:

(0,4)

Putting x=0 and y = 4 in both equations

$-0.1(0)-0.3(4)=1.2\\0-1.2 =1.2\\-1.2 \neq 1.2\\0.2(0)-0.5(4)=2\\0-2 = 2\\-2 \neq 2$

This is not the correct answer as both equations are not true with this solution

For Option B:

(0,-4)

Putting x = 0 and y = -4 in both equations

$-0.1(0)-0.3(-4)=1.2\\0+1.2 = 1.2\\1.2 = 1.2\\0.2x-0.5y=2\\0.2(0)-0.5(-4) = 2\\2 = 2$

Both equations are true for (0,-4) hence it is the solution of the system.

For Option C:

(4,0)

$-0.1(4)-0.3(0)=1.2\\-0.4-0 = 1.2\\-0.4 \neq 1.2\\0.2x-0.5y=2\\0.2(4)-0.5(0) = 2\\0.8 \neq 2$

Not true for both equations

Hence,

Option b is the correct answer.

7 0

2 years ago

How many years has it been since the Parthenon had begun?

horsena [70]

15 years since the Parthenon had begun

4 0

2 years ago

Chocolate chip cookies have a distribution that is approximately normal with a mean of 24.2 chocolate chips per cookie and a sta

Allisa [31]

Answer:

Percentile 5

$z=-1.64$

And if we solve for a we got

$a=24.2 -1.64*2.6=19.94$

Percentile 95

$z=1.64$

And if we solve for a we got

$a=24.2 +1.64*2.6=28.46$

Step-by-step explanation:

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(24.2,2.6)$

Where $\mu=24.2$ and $\sigma=2.6$

We want to find the percentiles 5 and 95 for this case.

Percentile 5

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.95$ (a)

$P(X$ (b)

We want to find a percentile with 0.95 of the area on the left and 0.05 of the area on the right it's z=-1.64. On this case P(Z<-1.64)=0.05 and P(z>-1.64)=0.05

Using this condition we got:

$P(X$

$P(z$

Replacing we got:

$z=-1.64$

And if we solve for a we got

$a=24.2 -1.64*2.6=19.94$

Percentile 95

$z=1.64$

And if we solve for a we got

$a=24.2 +1.64*2.6=28.46$

4 0

2 years ago

Someone please answer this for me :(

Zarrin [17]

Answer:

3,4

Step-by-step explanation:

5 0

2 years ago