In the compound nh3, nitrogen has an oxidation number of 3+ and hydrogen has an oxidation number of -1
The molecule NH3 have a neutral charge so the number of oxidation number of it's component must be equal to zero. The molecule NH composed of 1 nitrogen and 3 hydrogens. If the nitrogen oxidation number is 3+, then hydrogen would be:
1* N + 3*H=0
1*+3 +3*H=0
3H= -3
H= -1
<u>Given:</u>
Enthalpy change (ΔH) for SO3 decomposition = +790 kJ
Moles of SO3 = 2.1 moles
<u>To determine:</u>
Energy required when 2.1 moles of SO3 reacts
<u>Explanation:</u>
The decomposition reaction is -
2SO3(g) → 2S(s) + 3O2 (g)
Energy required when 2 moles of SO3 reacts is 790 kJ
Thus, for 2.1 moles of SO3 the energy requirement would be
= 2.1 moles SO3 * 790 kJ/2 moles SO3 = 829.5 kJ
Ans: 830 kJ are required when 2.1 moles of SO3 reacts.
