Option 1 skjjeskjeejjxjjjd
Answer:
Third sequence (7, 2, 1, -4, -10)
In the first sequence, -4 has to be in front of -10 because it is larger.
In the second sequence, 7 goes in the beginning, with 2 then 1 following, with -4 behind and -10 behind -4.
In the third option, 7 must be in the front, with 2, 1, then -4, then -10 following.
The answer = third sequence.
Hope it helped!
Answer:
This is very detailed as I wish to make some principles about fractions clear.
3
5
12
Explanation:
This question boils down to
3
2
3
−
1
4
A fractions structure is that of:
count
size indicator of what you are counting
→
numerator
denominator
You can not directly add or subtract the counts (numerators) unless the size indicators (denominators) are the same.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Consider
3
2
3
Write as
3
+
2
3
Multiply by 1 and you do not change the value. However, 1 comes in many forms so you can change the way something looks without changing its true value
[
3
×
1
]
+
2
3
[
3
×
3
3
]
+
2
3
9
3
+
2
3
=
11
3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Putting it all together
3
2
3
−
1
4
→
11
3
−
1
4
But the size indicators are not the same. I chose to make them become 12
11
3
−
1
4
→
[
11
3
×
1
]
−
[
1
4
×
1
]
→
[
11
3
×
4
4
]
−
[
1
4
×
3
3
]
→
44
12
−
3
12
Now we may subtract the counts
→
44
−
3
12
=
41
12
But this is the same as
12
12
+
12
12
+
12
12
+
5
12
=
1
2
+
2
1
2
+
2
1
2
+
5
12
=
3
5
12
Step-by-step explanation:
Answer:
A: (-3,4) (-3,6) (-5,6) (-7,4)
B: The transformation would be described as a reflection over the y axis
C: The transformation does result in a congruent figure because the shape doesn't change in size or shape and in length or width
Step-by-step explanation:
So our plots from the figure are: (3,4) (3,6) (5,6) (7,4)
So using the rule (x, y) → (-x, y) are new points would be:
(-3,4)
(-3,6)
(-5,6)
(-7,4)
This rule (x, y) → (-x, y) is used for the type of transformation that is a reflection but over the y axis.
Answer:
x = 4
y = 1
Step-by-step explanation:
Here, we want to solve the system of equation using elimination method
We have this as follows;
3x + y = 13
4x- 3y = 13
Multiply equation 1 by 3
9x + 3y = 39
4x-3y = 13
Add the two equations
13x = 52
x = 52/13
x = 4
From equation 1;
3x + y = 13
y = 13-3x
y = 13-3(4)
y = 13-12 = 1
