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2 years ago

1/2 (4 - 2x); 2-2x can some one help

Mathematics

1 answer:

lakkis [162]2 years ago

7 0

Answer:

x=0

Step-by-step explanation:

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If you are asked to find 621 / 59 how do you know the quotient will be greater than 10 before you actually divide?

vova2212 [387]

You will know that it is greater than 10 because it goes into 621 more than 10 times

6 0

2 years ago

10 over h equals 52 over 13. Represent for h.

kupik [55]

1. 10/h = 52/13

2. 10/h = 4

3. 10 / 4 = 2.5

10/2.5 = 52/13

h = 2.5

6 0

4 months ago

F(x) = (x − 6)2 − 31

eimsori [14]

Answer:

2x -43

Step-by-step explanation:

Distribute 2 to into the parenthesis: 2 * x and 2 * -6

2x + -12 - 31

Combine like-terms: -12 + - 31 = -43

2x -43

IF you need the equation completely simplified, I bEliVe you would be able to divide by 2 to get it: x - 21.5

5 0

2 years ago

Carter has 43 coins, all nickels and dimes in his piggy bank. The value of the coins is $3.65. How many dimes does Carter have?

kvasek [131]

the value of 43 and 3.65 is you use kfc chicken because when you angry or very mad you need some kfs chicken bye.

3 0

2 years ago

Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3

Maru [420]

Answer:

Fourth term: $a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{3}$ = $\sqrt{3}$

Fifth term: $a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{4}$ = 1

Sixth term: $a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}$

Step-by-step explanation:

The geometric progression is:

$9, 3 \sqrt{3}, 3...$

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

$r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}$

That is the common ratio.

Geometric progression is given generally as:

$a_n = ar^{(n - 1)}$

where a = first term

r = common ratio

$a_n$ = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: $a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{3}$ = $\sqrt{3}$

Fifth term: $a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{4}$ = 1

Sixth term: $a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}$

5 0

2 years ago

1/2 (4 - 2x); 2-2x can some one help​

1/2 (4 - 2x); 2-2x can some one help