Answer:
18
Step-by-step explanation:
The area of triangle is b*h/2
so it will be 36/2 which will be 18
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Answer and Explanation:
Given : The random variable x has the following probability distribution.
To find :
a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.
b. Calculate the expected value of x.
c. Calculate the variance of x.
d. Calculate the standard deviation of x.
Solution :
First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.25 0 0 0
1 0.20 0.20 1 0.20
2 0.15 0.3 4 0.6
3 0.30 0.9 9 2.7
4 0.10 0.4 16 1.6
∑P(x)=1 ∑xP(x)=1.8 ∑x²P(x)=5.1
a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.
Yes it is a probability distribution.
b) The expected value of x is defined as
c) The variance of x is defined as
d) The standard deviation of x is defined as
Based on the information represented by the boxplot ;
- Latasha's lowest sale amount = 50
- Kayla's median is between 200 and 300
- Latasha has a greater spread due to higher IQR value
1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>
- The minimum value is denoted by the starting position of the lower whisker on a boxplot.
- Lowest amount of sale made by Latasha = 50
2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>
- 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.
- 50% of sales made by Kayla is between 200 and 300
- With median sale value being 250
3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>
- The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution
- IQR = Upper Quartile (Q3) - Lower quartile(Q1)
<u>For Latasha</u> :
- Q3 = 450 (Endpoint of the box)
- Q1 = 150 (starting point of the box)
<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>
- Q3 = 375 (Endpoint of the box)
- Q1 = 100 (starting point of the box)
- IQR = 375 - 100 = 275
- Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.
Learn more :brainly.com/question/24582786
Answer:
x = 7
x = -5
Step-by-step explanation:
Given
x² - 2x - 35 = 0
Consider the factors of the constant term (- 35) which sum to give the coefficient of the x- term (- 2)
The factors are - 7 and + 5, since
- 7 × 5 = - 35 and - 7 + 5 = - 2, thus
(x - 7)(x + 5) = 0
Equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
x - 7 = 0 ⇒ x = 7