Answer:
t = 3.52 s
Explanation:
Given that,
The deceleration of a car is, a = -1.7 m/s²
The initial velocity of the car, u = 15 m/s
Final velocity of the car, v = 9 m/s
We need to find the time that is required to slow the car from 15 m/s to 9 m/s. The definition of acceleration is :
So, it will take 3.52 seconds to slow the car from 15 m/s to 9 m/s.
The force between the two particles will quadruple
Explanation:
The magnitude of the electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
d is the separation between the two charges
In this problem, let's call F the initial force between the two charges, when they are at a distance of d.
Later, the distance between the two particles is halved, so the new distance is:
This means that the new electrostatic force will be:
Therefore, the force between the two particles will quadruple.
Learn more about electrostatic force:
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Answer:
10^6 Pa
Explanation:
Radius of the opening, r = 0.491 mm = 0.491 x 10^-3 m
Force, F = 0.763 N
Pressure is defined as the thrust acting per unit area. Its SI unit is Pascal.
Pressure = force / Area
Area, A = πr² = 3.14 x 0.491 x 10^-3 x 0.491 x 10^-3 = 7.57 x 10^-7 m^2
Pressure
P = 1 x 10^6 Pascal
Thus, the pressure inside the pot is 10^6 Pa.