Answer:
To calculate how many total miles Rachel runs per minute, setting up a unit rate, that is a rate with a denominator of 1, would be helpful.
Step-by-step explanation:
Use the current problem to determine a rate.
23 minutes/4 miles
Now, set up a unit rate.
1 minute/<em>x </em>miles = 23 minutes/4 miles
To solve for <em>x, </em>we can use simple division strategies. We divide 23 by 23 to receive 1 minute. Likewise, dividing the current milage by 23 would wield the correct unit rate. To do this, divide 4 by 23.
4/23 = 0.1739130434782609
Finally, simplify your answer to receive 0.17.
Therefore, Rachel runs ~0.17 miles per minute. (Note that this answer is only a rounded answer of her actual milage per minute)
Answer:
5.0 ft - 5.6 ft
Step-by-step explanation:
Given that the structure is to be made using two 12 foot boards, then we expect the total perimeter to be equal to (2*12)= 24 ft.
Using the angle of elevation, 40° and the width of 8 ft then you can apply the formula for tangent of a triangle where ;
Tan α = opposite side length/adjacent length
Tan 40°= h/8
h= 8 tan 40° = 6.71 ft
Applying the cosine of an angle formula to find the length of the sliding side
Cosine β = adjacent length /hypotenuse
Cosine 40°= 8/ sliding side length
sliding side length = 8/cosine 40° =10.44 ft
Checking the perimeter = 10.44 +8+6.71= 25.15 ft
This is more than the total lengths of the boards, so you need to adjust the height as;
24 - 18.44 = 5.56 ft ,thus the height should be less or equal to 5.56 ft
h≤ 5.6 ft
<span>So we need to see how does the decimal point change it's place in the quotient when we divide any number by increasing powers of 10. Lets start with number 1. The decimal point is: 1.0 and when we divide by 10^1=10 we get 1/10=0.1. The decimal point has moved one place to the left. Now lets divide 1 by 10^2 and we get 1/100=0.01. Again, the decimal point has moved one more place to the left. Now: 1/10^3 = 1/1000 = 0.001. Next would be 0.0001, next one would be 0.00001 and so on. </span>
We need the values to answer this question