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soldier1979 [14.2K]

2 years ago

10

Can someone help me with this question

1 answer:

exis [7]2 years ago

5 0

Answer:

Angle A + Angle B + Angle C = 180° (LP)

3x+5 + 5x-18 + 7x-2 = 180

3x +5x + 7x = 180 +15

15x = 195

x=195/15

x=13

Angle A: 3x + 5 = 3 x 13 + 5 = 44

Angle B: 5x - 18 = 5 x 13 - 18 = 47

Angle C: 7x - 2 = 7 x 13 - 2 = 89

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Please help??! Solve by elemination <br>4x + y = 6<br>12x + 3y = 18<br>Show your work

RUDIKE [14]

Multiply -3[4x+y=6].
This gets you -12x-3y=-18.
Add the two equations together to eliminate the y.
-12x - 3y = -18
+ 12x + 3y = 18
------------------------
0 = 0
This means that these are in fact the same line, therefore there are infinite solutions.

8 0

3 years ago

4 x 6 - 8 / 4 = help me out

nydimaria [60]

Answer:

22

Step-by-step explanation:

You use the order of operations: PEMDAS.

Sooo...

4*6-8/4=

24-8/4=

24-2=

22

4 0

2 years ago

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Allushta [10]

The answer is going to be 35 :)

5 0

2 years ago

I need help on these three!!!

saw5 [17]

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8 0

3 years ago

50 POINTS PLZ HELP NEED THIS DONE ASAP

solmaris [256]

Answer-

the standard form of the function is,

$f(x)=-\frac{1}{2}x^2+6x+45$

<u>Solution-</u>

The standard form of the function is,

$f(x)=ax^2+bx+c$

Taking the points as (0, 45), (2, 55), (4, 61)

Then putting (0, 45) in the equation,

$\Rightarrow 45=a(0)^2+b(0)+c\\\\\Rightarrow c=45$

Then putting (2, 55) with the value of c in the equation,

$\Rightarrow 55=a(2)^2+b(2)+45$

$\Rightarrow 4a+2b=10$ -------1

Then putting (4, 61) with the value of c in the equation,

$\Rightarrow 61=a(4)^2+b(4)+45$

$\Rightarrow 16a+4b=16$ ------ 2

Solving equation 1 and 2, we get,

$\Rightarrow a=-\frac{1}{2},\ b=6$

Putting the values of a, b, c in the standard form,

$f(x)=-\frac{1}{2}x^2+6x+45$

8 0

2 years ago