I think the answer is 39/250
Answer: The required equation is and the number of fishes in the pond on June 1 = 115
Step-by-step explanation:
Given: The number of fishes in pond on July 1 = 63
Also, it is said that the number of fishes in pond on July 1 is 52 fewer(lesser) than the number of fishes in pond on June 1.
Let f be the number of fishes in pounds on June 1.
then the required equation will be
Now, add 52 on both the sides of the equation, we get
You have to figure out the highest common factor of each set of values:
9a + 21 = 3(3a + 7)
21b - 49 = 7(3b - 7)
54 - 6c = 6(9 - c)
8a + 32b = 8(a + 4b)
4p + 28q + 8r = 4(p + 7q +2r)
84a - 36b -12c = 6(14a - 6b - 2c)
6p + 9q + 15r = 3(2p + 3q + 5r)
18s - 30t + 54u = 6(3s - 5t + 9u)
Hope this helps :)
The 3 digits in the unit period is 817
Total length of the string = yard
Length of string used for craft = of total length of string
= of
=
= yard
Length of the string left after use = Total length of the string - Length of string used for craft
Length of the string left after use =
=
Reducing it to the lowest term, we get
= yard
Therefore, the length of string left is yard.