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2 years ago

12

A scale drawing of a rectangular prism is 10cm by 8.5 cm. If the actual field has dimension of 40m by 34m, what scale can be use

d

1 answer:

Bad White [126]2 years ago

5 0

The answer will be D. Hope it help!

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4/16 in simplest form

vova2212 [387]

4 goes into 4 once, and then into 16 4 times. Making the final answer 1/4

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2 years ago

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Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

6 0

2 years ago

Perimeter of a rectangle is 15x+17y if the length is 7/2x+7y then find the width of the rectangle

bogdanovich [222]

The perimeter of a rectangle is given by the formula,

$P=2l+2w$

We substitute,

$P=15x+17y$

and

$l=\frac{7}{2}x+7y$

into the above formula to obtain the expression,

$15x+17y=2(\frac{7}{2}x+7y)+2w$

$15x+17y=7x+14y+2w$

We now group the x and y terms on the Left Hand Side of the equation to get.

$15x-7x+17y-14y=2w$

$8x+7y=2w$

We now divide through by 2 to get,

$4x+\frac{7}{2}y=w$

Therefore the width of the rectangle is

$4x+\frac{7}{2}y$

8 0

2 years ago

Triangle ABC is shown Translate Triangle ABC 5 units left and 4 units up and reflect it over the x-axis

tekilochka [14]

Here is my process for solving this.

First I drew arrows that indicated I was moving the whole triangle 5 units to the left.

*Look at first attachment*

Then I drew another triangle using those new points. (The new triangle is in pink)

*Look at second attachment*

Then I drew arrows that moved this new triangle 4 units up. (The new arrows are in pink)

*Look at third attachment*

Then I drew the new triangle in blue using the new points.

*Look at fourth attachment*

Then I mirrored / reflected the triangle over the x axis (the horizontal line) In green.

*Look at fifth attachment*

The fifth attachment in green is the final product! Hope that helps.

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1 year ago

HELP! What is the greatest common factor of 20a2b2 and 50b3?

GREYUIT [131]

Answer: 10b^2
Good luck.

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2 years ago

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