You can't really determine the amount of computers from this question, they're obviously not going to have one computer for everyone so half third, or even a fourth of the school population
Answer:
–16 – 22i
Step-by-step explanation:
The radius of the circle = 4 + 26i - (-6 + 2i)
= 10 + 24i.
The radius will be the absolute values of this |10 + 24i|.
If a point is on the circle then it's distance from the centre must be 10+ 24i.
-19 + 15i - (-6 + 2i) = -13 - 13i , so this is not on the circle.
-16 - 22i - (-6 + 2i) = -10 - 24i = |10 + 24i| , so this is on the circle.
5 + 16i - (-6 + 2i) = 11 + 14i , so this is not on the circle.
20 - 24i - (-6 + 2i) = 26 - 26i. so this is not on the circle.
0.95
Consider this question in terms of percentages ( that is, out of 100)
she got 95 questions right → 95% = 
= 0.95
What you want is P(6∩1) or P(1∩6) or P(2∩5) or P(5∩2) or P(3∩4) or P(4∩3).
The events of rolling the dice are independent (i.e. they don't affect one another) so:
E.g.
P(6∩1) = P(6) * P(1)
P(2∩5) = P(2) * P(5)
The probability of getting a given number on a roll is 1/6 for both dice.
So:
P(6∩1) = 1/6 * 1/6 = 1/36
This is the same for any arrangement of numbers you could get from rolling two dice.
So, we can see that there are 6 arrangements of numbers that will give a sum of 7 and so that is 6 * 1/36 = 6/36 = 1/6
